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bogdanovich [222]
3 years ago
14

A 60 and N net force is applied to a 12 kg box which is the acceleration of the box?

Chemistry
1 answer:
GarryVolchara [31]3 years ago
6 0

The relation between force and mass and acceleration is

Force = mass X acceleration

The SI unit will be

Force = Newton

mass =kg

acceleration=\frac{m}{s^{2} }

thus

acceleration = \frac{Force}{mass}

putting values

acceleration=\frac{60 N}{12kg}=5\frac{m}{s^{2} }

Thus the acceleration will be

5\frac{m}{s^{2} }

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You weigh a 24K gold chain and find that it weighs 400 grams. Determine home many moles of gold atoms you have
makkiz [27]

Answer:

                     2.03 moles of Gold

Explanation:

                     Gold is one of the most precious metal metal used in many applications and mainly as a jewellery. In terms of purity it is categorized in Karats. 24 Karat is considered the purest Gold (i.e. 100 % Gold) while other Karats (14, 18, 22 e.t.c) are alloys with other metals and gyms.

Data Given:

                 Mass of Gold  =  400 g

                 A.Mass of Gold  =  196.97 g.mol⁻¹

Calculate Moles of Gold as,

                              Moles  =  Mass ÷ M.Mass

Putting values,

                              Moles  =  400 g ÷ 196.97 g.mol⁻¹

                              Moles  =  2.03 moles of Gold

4 0
3 years ago
Sarah is making a strawberry banana smoothie. She combines one banana, five strawberries, and a cup and a half of milk in a
NeTakaya

Answer:

homogeneous substance

8 0
3 years ago
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A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w
Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)

c=5760J/^oC

\Delta T=0.570^oC

To calculate the enthalpy change, we use the formula:

\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = \frac{3283.2J}{0.1326g}=24760.181J/g

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol

4 0
3 years ago
A chemical reaction involves reactant species A, B, and C. Leaving all other factors identical, doubling the concentration of sp
umka21 [38]

Answer:

Rate = k . [B]² . [C]

Explanation:

The dependence of the reaction rate on the concentration of the reactants is given by the reaction order of each one, as shown in the rate equation.

Rate=k.[A]^{x} .[B]^{y} .[C]^{z}

where,

k is the rate constant

x, y, z are the reaction orders.

  • <em>The rate of reaction is not affected by changing the concentration of species A.</em> This means that the reaction order for A is x = 0 since when its concentration changes, the rate stays the same.
  • <em>Leaving all other factors identical, doubling the concentration of species B increases the rate by a factor of 4.</em> This means that the reaction order for B is y = 2, so when the concentration is doubled, the new rate is 2² = 4 times the initial rate.
  • The rate of the reaction is linearly dependent on the concentration of C. This means that the reaction order for C is z = 1, that is, a linear dependence.

All in all, the rate equation is:

Rate = k . [B]² . [C]

3 0
3 years ago
How does liquid carbon dioxide connect to organic chemistry <br> please I need long answers
inessss [21]
Carbon dioxide can’t exist in three states; Gas, Liquid & Solid. At normal temperatures and pressures, CO2 is colorless with a slightly pungent odor at high concentrations. If compressed and cooled to proper temperature the gas liquifies. Solid CO2, (dry ice) sublimates back to the natural gaseous state.
7 0
3 years ago
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