Question

Use the quadratic formula to solve the equation -4x^2-3x+2=0

Answer 1

The quadratic formula is hard to type on this 
3 (+ , -) (sqroot of 41)
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              8

Answer 2

Answer:

The solution to the quadratic equations are:

$x=-\frac{3+\sqrt{41}}{8},\:x=\frac{\sqrt{41}-3}{8}$

Step-by-step explanation:

Consider the provided quadratic equation.

$-4x^2-3x+2=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a=-4, b=-3 and c=2 in above formula.

$x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\left(-4\right)2}}{2\left(-4\right)}$

$x_{1,2}=\frac{3\pm\sqrt{9+32}}{-8}$

$x_{1,2}=-\frac{3\pm\sqrt{41}}{8}$

Hence, the solution to the quadratic equations are:

$x=-\frac{3+\sqrt{41}}{8},\:x=\frac{\sqrt{41}-3}{8}$