All categories

2 years ago

Use the quadratic formula to solve the equation -4x^2-3x+2=0

Mathematics

2 answers:

Karolina [17]2 years ago

7 0

The quadratic formula is hard to type on this
3 (+ , -) (sqroot of 41)
---------------------------
8

Stolb23 [73]2 years ago

5 0

Answer:

The solution to the quadratic equations are:

$x=-\frac{3+\sqrt{41}}{8},\:x=\frac{\sqrt{41}-3}{8}$

Step-by-step explanation:

Consider the provided quadratic equation.

$-4x^2-3x+2=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a=-4, b=-3 and c=2 in above formula.

$x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\left(-4\right)2}}{2\left(-4\right)}$

$x_{1,2}=\frac{3\pm\sqrt{9+32}}{-8}$

$x_{1,2}=-\frac{3\pm\sqrt{41}}{8}$

Hence, the solution to the quadratic equations are:

$x=-\frac{3+\sqrt{41}}{8},\:x=\frac{\sqrt{41}-3}{8}$

You might be interested in

Violet used 1 3/4 gallons of paint on her kitchen walls. She used 4 times as much paint for her living room and bedroom walls. H

beks73 [17]

The answer is 4 x 1 3/4 =4 12/16

7 0

2 years ago

Read 2 more answers

Plz help me asap worth 20 points

Ainat [17]

Answer:

OK so the equation has a exponent so if there is a exponent then you need to multiply. since 227 is the Area and the exponent is 2.

Step-by-step explanation:

3 0

2 years ago

Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then

Debora [2.8K]

To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form $f(x)=x^2+bx+c$ it vertex $(h,k)$ is given by $h= \frac{-b}{2a}$ , $k=f(h)$ .
We can infet from our parabola that $a=2$ and $b=-12$ . So lets replace those values in our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-12)}{2(2)}$
$h= \frac{12}{4}$
$h=3$
$k=f(h)=2(3)^2-12(3)+19$
$k=2(9)-36+19$
$k=18-17$
$k=1$
The vertex $(h,k)$ of our parabola is $(3,1)$

Now to find our second point, we are going to evaluate our parabola at $x=0$
$f(0)=2(0)^2-12(0)+19$
$f(0)=0+0+19$
$f(0)=19$
Our second point is $(0,19)$

We can conclude that we can graph the parabola $f(x)=2x^2-12x+19$ using its vertex $(3,1)$ and the point $(0,19)$ as follows:

7 0

2 years ago

Find the measure of the exterior Angle1 (I’m a bit confused on how exterior angles work)

sergejj [24]

Answer:

Step-by-step explanation:

I would do 40 + 30 = 70

180-70 = 110

110 is the last angle bc all angles add to 180 in a triangle

Then 180 - 110 = 70 for angle 1 because their supplementary

I don't know if you could just add the 2 inside angles but I would do it this way to be safe until I know for sure.

7 0

2 years ago

Find the square root by factor <br>21904

mihalych1998 [28]

$21904|2\\10952|2\\.\ 5476|2\\.\ 2738|2\\.\ 1369|37\\.\ \ \ \ 37|37\\.\ \ \ \ \ \ 1|\\\\21904=2\times2\times2\times2\times37\times37=2^4\times37^2\\\\\sqrt{21904}=\sqrt{2^4\times37^2}=\sqrt{2^4}\times\sqrt{37^2}=2^2\times37=4\times37=148$

$\sqrt{21904}=\sqrt{4\times5476}=2\sqrt{4\times1369}=2\times2\sqrt37\times37}=4\times37=148$

8 0

2 years ago

Read 2 more answers