Answer:
a)polynomial highest degree of polynomial = 5
b) polynomial highest degree of polynomial = 6
c)polynomial highest degree of polynomial = 4
d)polynomial highest degree of polynomial = 1
e) polynomial highest degree of polynomial = 0
f)polynomial highest degree of polynomial = 5
g)polynomial highest degree of polynomial =4
h)polynomial highest degree of polynomial = 8
i)polynomial highest degree of polynomial =6
j)polynomial highest degree of polynomial =4
k)polynomial highest degree of polynomial =8
i)polynomial highest degree of polynomial =4
Hope it helps
<h3>
<u>Explanation</u></h3>
f(a) means the value of f(x) is ... when x = a. That means if we substitute x = 3, we would get f(3).
f(3) also means the value of f(x) is ... when x = 3.
f(x) can also be defined as y // f(x) = y
You can find the value of f(x) at specific domain from the graph by looking at x = 3 then look up to where the point or where the graph passes. From the graph, when x = 3 as we look up and the graph passes y-coordinate at 1.
Therefore we can say that when x = 3, y = 1.
<h3>
<u>Answer</u></h3>
f(3) = 1
I think its 4910.00 you can't make a whole number a decimal.
Example :
x y
1 3
2 6
3 9
4 12
first thing u do is pick any 2 points (x,y) from ur table
(1,3) and (2,6)
now we sub those into the slope formula (y2 - y1) / (x2 - x1) to find the slope
(y2 - y1) / (x2 - x1)
(1,3)....x1 = 1 and y1 = 3
(2,6)...x2 = 2 and y2 = 6
sub
slope = (6 - 3) / (2 - 1) = 3/1 = 3
now we use slope intercept formula y = mx + b
y = mx + b
slope(m) = 3
use any point off ur table...(1,3)...x = 1 and y = 3
now we sub and find b, the y int
3 = 3(1) + b
3 = 3 + b
3 - 3 = b
0 = b
so ur equation is : y = 3x + 0....which can be written as y = 3x...and if u sub any of ur points into this equation, they should make the equation true....if they dont, then it is not correct
and if u need it in standard form..
y = 3x
-3x + y = 0
3x - y = 0 ...this is standard form
Answer:
10.67 m
Step-by-step explanation:
Velocity is given as;
v(t) = t² − t − 6
To get the distance, we will integrate the velocity equation.
x(t) = ∫v(t) = (t³/3) - (t²/2) - 6t
Thus, from t=0 seconds to t=4 seconds., we have;
(t³/3) - (t²/2) - 6t between 0 and 4.
Thus;
Total Distance = [(4³/3) - (4²/2) - 6(4)] - [(0³/3) - (0²/2) - 6(0)]
Total distance = (64/3) - 8 - 24 = -10.67 m
Distance can't be negative and so we take the absolute value which is 10.67 m
