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adelina 88 [10]
3 years ago
9

How many cents is equal to $ ¼?

Mathematics
2 answers:
Pavel [41]3 years ago
5 0

Answer:

25 cents

Step-by-step explanation:

Nataliya [291]3 years ago
5 0

Answer:

25 cents

Step-by-step explanation:

25 cents times 4 is $1

think of quarters

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EXTRA POINTS<br> x/4 ÷ 2/3 = 1/5 solve for x
nikitadnepr [17]

Answer:

x=40

Step-by-step explanation:

first you simplify both sides of the equation, then you isolate the variable

40/4= 10

10 times 3/2 = 15

8 0
2 years ago
For better clarification I guess
marissa [1.9K]

Answer:

1.) =\frac{\sqrt{3}}{3}

2.) 42\sqrt{30}

Step-by-step explanation:

1.) \mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{3}}{\sqrt{3}}

2.) \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{b}=\sqrt{a\cdot b}

\sqrt{6}\sqrt{5}=\sqrt{6\cdot \:5}

6 0
3 years ago
Find the distance between the points (-3,14) and (4,-10)
Jobisdone [24]

Answer:

The answer is -3.4. If you have to round it, round it down to 3.

Step-by-step explanation:

7 0
3 years ago
What is a million times all the numbers in the world
kozerog [31]
Well, there isn’t really an end for numbers...

However; The biggest number referred to regularly is a googolplex (10googol), which works out as 1010^100. That isn’t the end to numbers but it is a huge one. We will replace that with ‘all the numbers in the world’.

106 is the exponent equivalent to 1 million

So your question would be:
106 x 1010^100 =

However I don’t believe there is a calculator that large.
7 0
3 years ago
Given that f(a+b)= f(a) + f(b) and f(x) is always positive, what os the value of f(0)?
FrozenT [24]
This is a strange question, and f(x) may not even exist. Why do I say that? Well..

[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).

[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!

Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.

To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
4 0
3 years ago
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