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N76 [4]
3 years ago
5

Your friend tossed a fair coin when you weren’t around. She has a habit of messing with you every once in a while, and so there

is a 1/3 chance that she will lie to you about the result of the coin toss (report heads as tails and tails as heads), and 2/3 chance that she will tell you the true result of the coin toss. Suppose she claims that the coin toss resulted in heads. What’s the probability that she’s lying?
Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that your friend tossed a fair coin when you weren’t around.

Let A be the event that she said the outcome is head

B1 = Event she lied and B2 = Event she did not lie

P(B1) = \frac{1}{3}    \\ P(B2) \frac{2}{3}

P(AB1) = \frac{1}{2} *\frac{1}{3} =\frac{1}{6}

P(AB2) = \frac{2}{3} \frac{1}{2} =\frac{2}{6}

Required probability = P(B1/A)=\frac{P(B1A)}{P(B1A)+P(B2A)} \\=\frac{\frac{1}{6} }{\frac{1}{6}+\frac{2}{6}} \\=\frac{1}{3}

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Using the formula in the attached:
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2.) Using the mean, calculate (xi - μ)² for each value:
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3.) Sum the squared differences and divide by n - 1.
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3 years ago
christa went shopping for back to school clothes.Before the tax was added on, her total was $176. if the sales tax is 6% what wa
skelet666 [1.2K]
<span>Christa went shopping for back to school clothes.
She paid a total of 176 dollars before the tax was added on.
Now, how much will she be paying if the sales tax is 6% what was the total amount she paid.
Solutions:
=> 176 dollars * 6% to get the amount
=> 6% / 100% = 0.06
=> 176 dollars * .06 = 10.56
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=> 176 dollars + 10.56 dollars = 186.56 dollars</span>



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