9514 1404 393
Answer:
128 miles
Step-by-step explanation:
The convict has a head start of ...
distance = speed × time
distance = (8 mi/h) × (14 h) = 112 mi
That distance is being closed at a rate that is the difference between the speeds, so ...
64 mi/h -8 mi/h = 56 mi/h
The time it takes the guards to catch the convict will be ...
time = distance/speed
time = (112 mi)/(56 mi/h) = 2 h
The guards and prisoner will be at a distance from the prison of ...
distance = speed × time
distance = (64 mi/h)(2 h) = 128 mi
The convict will be caught 128 miles from the prison.
__
<em>Check</em>
The convict will run an additional (8 mi/h)(2 h) = 16 mi after the guards start pursuit. That, in addition to the 112 miles already run, will total 112+16=128 miles, the same distance the guards travel in that 2 hours.
Answer:0.47 cents per cup
Step-by-step explanation:
Since they’re are 32 cups in 2 gallons, we can divide $15.04 by 32 and get the answer
Answer:
2x^1+1
Step-by-step explanation:
Area=L X W
which means that (14x^4+7x^2) needs to be divided by 7x^2
factorise(14x^4+7x^2) which gives 7x(2x^2+1)
divide 7x(2x^2+1) by 7x^2
gives 2x^2 +1
(k - 1)(k - 4)
Use FOIL to solve this.
First
k * k
Outer
k * -4
Inner
-1 * k
Last
-1 * -4
k^2 - 4k - 1k + 4
k^2 - 5k + 4 is the trinomial.
Answer:
45
Step-by-step explanation:
Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.
m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1
The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.
m(arc)EVL + m(arc)EHL = 360
m(arc)EVL = 360 - m(arc)EHL Eq. 2
We are given this:
m<EYL = (1/3)m(arc)EHL Eq. 3
Substitute equations 2 and 3 into equation 1.
(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]
Now we have a single unknown, m(arc)EHL, so we solve for it.
2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]
2m(arc)EHL = 1080 - 6m(arc)EHL
8m(arc)EHL = 1080
m(arc)EHL = 135
Substitute the arc measure just found in Equation 3.
m<EYL = (1/3)m(arc)EHL
m<EYL = (1/3)(135)
m<EYL = 45
