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zmey [24]
3 years ago
11

The circle below is centered at the point (3,1) and has a radius of length 2. What is its equation?

Mathematics
2 answers:
Orlov [11]3 years ago
6 0

Answer:

The correct option is B.

Step-by-step explanation:

The standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

It is given that the center of the circle is (3,1) and the radius of the circle is 2.

The equation of the circle is

(x-3)^2+(y-1)^2=2^2

This equation is represents by option B, therefore option B is correct.

Paul [167]3 years ago
3 0
It is letter B.
Equation of a circle is in the form:
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the center of the circle with radius r.
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