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Ivanshal [37]
4 years ago
7

A box contains

Mathematics
1 answer:
Nezavi [6.7K]4 years ago
7 0
1/2 & 3/10 .. in simplest form

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Read 2 more answers
The population of a heard of cattle numbered was 5000 to begin with and was 10,000 after 10 years. If the population was growing
Lapatulllka [165]

Answer:

r=0.0718. The closest value from your given choices is C)r=0.69

Step-by-step explanation:

To solve this we are using the standard exponential growth equation:

f(t)=A(1+r)^t

where

f(t) is the final population after t years

A is the initial population

r is the growth rate in decimal form

t is the time in years

We know from our problem that the initial population is 5000, the final population is 10000, and the time is 10 years, so A=5000, f(t)=10000, and t=10.

Let's replace the values and solve for r:

f(t)=A(1+r)^t

10000=5000(1+r)^{10}

Divide both sides by 5000

\frac{10000}{5000} =(1+r)^{10}

2=(1+r)^{10}

Take root of 10 to both sides

\sqrt[10]{2} =\sqrt[10]{(1+r)^{10}}

\sqrt[10]{2} =1+r

Subtract 1 from both sides

\sqrt[10]{2}-1=r

r=\sqrt[10]{2}-1

r=1.0718-1

r=0.0718

We can conclude that the growth rate of our exponential equation is r=0.0718. The closest value from your given choices is C)r=0.69

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4 years ago
Please help me I will give brainliest
Scrat [10]

Answer:

Hm?

Step-by-step explanation:

Why should i

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