Seven increased by the product of two numbers Seven increased by the product of two numbers

Mathematics

2 answers:

kirill115 [55]3 years ago

7 0

<u>Answer:</u> The expression for the given statement is $7+(x\times y)$

<u>Step-by-step explanation:</u>

We are given a statement:

Seven increased by the product of two numbers

Let the first number be considered as 'x' and second number be considered as 'y'

'Increased' in the above statement means addition operation.

'Product' in the above statement means multiplication operation.

Hence, the expression for the given statement is $7+(x\times y)$

kipiarov [429]3 years ago

6 0

The answer would be 7+x*x the variables stand for the 2 unknown numbers and the product is the * symbol. Increased stands as the plus symbol. Hope this helps!

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<h2>D. $\frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\$ or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>

Step-by-step explanation:

Given the expression $\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }$ , the dfference is expressed as follows;

Step1: First we need to factorize the denominator of each function.

$\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }\\= \frac{x}{x^{2}-5x+3x-15 } - \frac{4}{x^{2} + 7x-5x - 35 }\\= \frac{x}{x(x-5)+3(x-5) } - \frac{4}{x( x+ 7)x-5(x +7) }\\= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\\\$

Step 2: We will find the LCM of the resulting expression

$= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\$