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2 years ago

EXPERT HELP I'LL GIVE BRAINLIEST:

Mathematics

2 answers:

Kipish [7]2 years ago

8 0

The answer is a! i hope this helps you!

taurus [48]2 years ago

3 0

I got the same thing you have

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21 = -3c + 7 -5c -2<br><br>i need help with this multi step equation question

belka [17]

Answer:

c=-2

Step-by-step explanation:

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2 years ago

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What number would you add to both sides of x2 + 7x = 4 to complete the square? 22 72 StartFraction 7 squared Over 2 EndFraction

ki77a [65]

Answer:

D on e2020

Step-by-step explanation:

got it right

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3 years ago

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Which symbol(s) represent SI units for temperature? Check all that apply.

Leviafan [203]

Answer:

K of Kelvin

Step-by-step explanation:

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3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!

Nookie1986 [14]

The answer is 2 3/10. how do you not know this

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2 years ago

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Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

2 years ago