Question

Help? Im lost with this one; someone tell me how

Answer 1

Rationalizing the denominator of $\frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }$

we get $\frac{\sqrt[3]{2} }{\sqrt[3]{z} }$.

Option D is correct.

Step-by-step explanation:

We need to rationalize the denominator: $\frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }$

Solving:

$\frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }$

using Radical rule: $\frac{\sqrt[n]{x}}{\sqrt[n]{y}}=\sqrt[n]{\frac{x}{y} }$

$=\sqrt[3]{\frac{2z}{z^2}}$

$=\sqrt[3]{\frac{2}{z^{2-1}}}$

$=\sqrt[3]{\frac{2}{z^{1}}}$

$=\sqrt[3]{\frac{2}{z}}$

We can write it as:

$\frac{\sqrt[3]{2} }{\sqrt[3]{z} }$

So, rationalizing the denominator of $\frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }$

we get $\frac{\sqrt[3]{2} }{\sqrt[3]{z} }$.

Option D is correct.

Keywords: Radical Expression

Learn more about Radical Expression at:

• brainly.com/question/7153188
• brainly.com/question/10534381

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