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3 years ago

I am a multiple of 70 I am between 300 and 500 I am 20 more than a multiple of 100 who am I?

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

8 0

#420

because 70x4=420 within 300 and 500 and is greater than 400 which is a multiple of 100

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The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$

$Q_3\text{ of data set 1}=3$

$\text{IQR of data set 1}=3-1=2$

$Q_1\text{ of data set 2}=1$

$Q_3\text{ of data set 2}=3$

$\text{IQR of data set 2}=3-1=2$

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0

3 years ago

Read 2 more answers

What is 33 %of what number is 1.45

Anna007 [38]

To find 33% of 1.45 we have to tranform 33% into decimal of traction
33% is 0.33 or $\frac{33}{100}$ and multiply if by 1.45
so
0.33*1.45=0.4785
or
1.45* $\frac{33}{100}= \frac{957}{2000}$

5 0

3 years ago

Can anyone help me please?

solong [7]

Answer:

i can what is it that u need help on?

Step-by-step explanation:

7 0

3 years ago

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ΔRST and ΔXYZ are equilateral triangles. The ratio of the perimeter of ΔRST to the perimeter of ΔXYZ is 1 to 3. The area of ΔRST

Nataliya [291]

For the scale factor of 1:3. Use ratio and proportion to solve for the area of the triangle.

area of triangle RST/ area of triangle XYZ = (1/3)^2
where
area of traianlge RST = 10.825 inch^2
Area of triangle XYZ= Area of triangle RST x (3)^2
Substitute the given values=97.4 inch^2

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3 years ago

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If the public debt of the Apex Union is 7,681,936,174,105,993 apex dollars And it's gross domestic product is 12,379,354,098,603

laila [671]

Answer:

The answer is True

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2 years ago