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GarryVolchara [31]
3 years ago
8

I am a multiple of 70 I am between 300 and 500 I am 20 more than a multiple of 100 who am I?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
8 0
#420

because 70x4=420 within 300 and 500 and is greater than 400 which is a multiple of 100
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The revised Daily Value for calcium is 1,300 mg per day. How many servings of this food would you have to eat to get 100% DV for
Ne4ueva [31]

Answer:

Taking into account the values showed for this food (image attached). It is required

5  

Servings.  

Step-by-step explanation:

The total calcium (Cat) required is 1300 mg/day.  

One serving of this food can have 260 mg.  

First step is to suppose one day of calculation. t = 1 day.

Cat = (1300 mg/day)(1 day) = 1300 mg Calcium.

One single serving can have 260 mg Calcium (Cas). So, we need to calculate the amount of servings (N) required to complete 1300 mg.

Cat = Cas*N

N = Cat/Cas = 1300 mg/260mg

N = 5.

Finally amount of servings is five N = 5.  

8 0
3 years ago
In right ∆LMN, sin M = 0.759. What is cos N? A. 0.121 B. 0.241 C. 0.349 D. 0.651 E. 0.759
Hatshy [7]

Answer:

E. 0.759

Step-by-step explanation:

You can take this right triangle to have a base length side LM , height of LN and a hypotenuse of MN

The sine of angle ∠LMN is 0.759, find the value of ∠LMN

sin^-1(0.759)=49.38

∠LMN=49.38°

Find angle ∠LNM

You know sum of angles in a triangle add up to 180°, given that this is a right-triangle, the base angle is 90° hence

∠LNM=180°-(90°+49.38°)

∠LNM= 180°-139.38°=40.62°

Find cos 40.62°

Cos 40.62°=0.7590

6 0
3 years ago
Given an 8 foot length of tree trunk with a radius of 3 feet, what is the volume of the tree trunk section? (to the nearest whol
trasher [3.6K]
The answer would be c)226. hope this helps!
5 0
3 years ago
Read 2 more answers
1 point
Firdavs [7]

9514 1404 393

Answer:

  (a)  2/100

Step-by-step explanation:

To determine the value of a digit, set all other digits to zero. Your digit has a value of ...

  0.020  . . .  two hundredths = 2/100

5 0
3 years ago
Read 2 more answers
Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0
3 years ago
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