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tekilochka [14]
3 years ago
10

.Write the quadratic equation in standard form that has x-intercepts at (-4/3,0) and (-3,0)

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

y = a(x² + (13/3)x + 12/3)

Step-by-step explanation:

First use the equation in x-intercept form: y = a(x-r)(x-s)

Where r and s are the values for the x-intercept

Substitute the x-intercepts

y = a(x - (-4/3)) (x - (-3))

Simplify

y = a(x + (4/3)) (x + 3)

Distributive property for brackets:

y = a(x² + 3x + (4/3)x + 12/3)

Find common denominator in fractions to collect like terms

y = a(x² + (9/3)x + (4/3)x + 12/3)

y = a(x² + (13/3)x + 12/3)

We cannot solve for the "a" value without another point.

If given the other point, substitute it for x and y to solve for a.

Then rewrite the equation with the "a" value.

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