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tekilochka [14]
3 years ago
10

.Write the quadratic equation in standard form that has x-intercepts at (-4/3,0) and (-3,0)

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

y = a(x² + (13/3)x + 12/3)

Step-by-step explanation:

First use the equation in x-intercept form: y = a(x-r)(x-s)

Where r and s are the values for the x-intercept

Substitute the x-intercepts

y = a(x - (-4/3)) (x - (-3))

Simplify

y = a(x + (4/3)) (x + 3)

Distributive property for brackets:

y = a(x² + 3x + (4/3)x + 12/3)

Find common denominator in fractions to collect like terms

y = a(x² + (9/3)x + (4/3)x + 12/3)

y = a(x² + (13/3)x + 12/3)

We cannot solve for the "a" value without another point.

If given the other point, substitute it for x and y to solve for a.

Then rewrite the equation with the "a" value.

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If two quantities <em>a</em> and <em>b</em> are directly proportional to one another, then both <em>a</em> and <em>b</em> change in the <u>same direction</u>.

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Both <em>a</em> and <em>b</em> don't necessarily change at the same rate, though, which means one of these needs to get appropriately scaled by some factor <em>k</em>, so that

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If instead <em>a</em> and <em>b</em> are inversely proportional, this means as one quantity changes, the other changes in the <u>opposite direction</u>.

Suppose I have two cups that I use for coffee that can both hold the same amount <em>k</em> if they are filled completely, but one cup is taller than the other. In order for both cups to be able to hold the same volume of coffee, the taller cup must have a thinner profile.

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