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3 years ago

Please please help idk what to do

Mathematics

2 answers:

KIM [24]3 years ago

4 0

2 is the answer, it goes up 2 and over 1. Keep in mind rise over run

dimaraw [331]3 years ago

4 0

2 is the correct answer

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Solve for [x]. The polygons in each 2x-20 16 16 8

Nataly_w [17]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:x = 16$

____________________________________

$\large \tt Solution \: :$

If two polygons are similar, their corresponding sides ratios will be equal to each other.

$\qquad \tt \rightarrow \: \cfrac{8}{16} = \cfrac{2x - 20}{24}$

$\qquad \tt \rightarrow \: \cfrac{1}{2} = \cfrac{2x - 20}{24}$

$\qquad \tt \rightarrow \: 2x - 20 = \cfrac{24}{2}$

$\qquad \tt \rightarrow \: 2x = 12 + 20$

$\qquad \tt \rightarrow \: 2x = 32$

$\qquad \tt \rightarrow \: x = 16$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0

2 years ago

2×7×7-3×3×3×2+3×2×2-6×6 I need an answer

Vadim26 [7]

Answer:

98-54+12-36

110-54-36

56-36

20Ans

3 0

2 years ago

Please help! Two math problems!!!

Fynjy0 [20]

Answer:

Tell me if i am wrong. :)

Step-by-step explanation:

To solve for y:

Q.1 2x + y = -1

y = -1 - 2x

Q. 2. 4x - 5y = 7

y = 7 - 4x over -5

3 0

3 years ago

What is the perimeter of the triangle? O 22 units O 30 units O44 units O 60 units

umka21 [38]

Answer:

22 units

Step-by-step explanation:

Add 12, 4 , and 6 and you will get 22

3 0

3 years ago

Read 2 more answers

Need answer to 4 and 5

algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3$ = 6

$g_3 = 2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9$ = 18

$g_4 = 2 . 3^{4 - 1} = 2 . 3^{3} = 2 . 27$ = 54

$g_5 = 2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81$ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $t_n = \frac{2}{3}t_{n - 1}$

$t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1 = \frac{2}{3}6$ = 4

$t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3}$

$t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9}$

$t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27}$

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0

3 years ago