The closed form sum of $$12 \left[ 1^2 \cdot 2 + 2^2 \cdot 3 + \ldots + n^2 (n+1) \right]$$ for $n \geq 1$ is $n(n+1)(n+2)(an+b)
.$ find $an +
b.$
1 answer:
n is an unspecified positive integer. If you want a single numerical result for the sum you must specify the value for n.
For example:
n = 5 means n(n+1)(n+2)(3n+1) = 3360
n=9 means n(n+1)(n+2)(3n+1) = 27720
etc.
The sum is a function of n.
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15/2 - 27/4
30 - 27/4
3/4
As simple as it can go is As it's multiplied out form, which is -42.
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Step-by-step explanation:
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0
Step-by-step explanation:
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I hope this is correct and have a great day