Can y'all help me please
1 answer:
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Answer:
Hence, the following equations, when graphed, intersect at the point (4, 0):
x - y = 4 (1)
x + y = 4 (4)
Step-by-step explanation:
<em>" For the graph to intersect at the point (4,0) we mean that when y=0 , x must be equal to 4 or we could say that when x=4 then y=0".</em>
1)
x-y=4
now when y=0 then x=4.
Hence, the graph intersect at the point (4,0).
2)
-x-y=4
When y=0 in the equation then x=-4, Hence the point (4,0) does not lie on the graph of the given function.
3)
2x-y=7
When y=0 then x=7/2.
Hence the graph of the function does not intersect at the point (4,0).
4)
x+y=4
When y=0 then x=4.
Hence the graph of the given function intersect at (4,0).
5)
2x + y = 7
When y=0 then x=7/2.
Hence the graph of the function does not intersect at the point (4,0).
6)
2x + y = -7
When y=0 then x= -7/2.
Hence the graph of the function does not intersect at the point (4,0).
