The values that exist two standard deviations above and below the mean are 681 and 265.
<h3>How to determine the values?</h3>
The given parameters exist:
Mean = 473
Standard deviation =104
The values above and below the mean exist calculated utilizing:

In this case n = 2.
So, we have, 
The value above is:
x = 473 + 2
104 = 681
The value below is:
x = 473 - 2
104 = 265
Therefore, the values that exist two standard deviations above and below the mean are 681 and 265.
To learn more about standard deviation refer to:
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The distance between (2,5) and (6,1) is:

The distance between the fourth vertex and (4,-1) should also be 4√2
The only point that gives us that distance is
B. (0,3)
Your final answer is
B. (0,3)
Answer:
cndjxnn
Step-by-step explanation:
vncnfxjdncnnxxjjxnxxnjxxjdnxnxjxj, x
Answer:
m = -2
Step-by-step explanation:
Slope formula ---
m = y2-y1/x2-x1
m = 5-9/8-6
m = -4/2
m = -2
Answer:
0 +256i
Step-by-step explanation:
According to Euler's formula, ...
(4 cis π/8)^4 = (4^4) cis (4×π/8) = 256 cis π/2 = 0 +256i
_____
"cis" is an abbreviation sometimes used for "cosine + i×sine". It simplifies writing the expression. Engineers sometimes simplify it further, writing 4∠(π/8) for the expression in this problem statement.