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3 years ago

Please help, I am literally freaking out.

Mathematics

1 answer:

Anon25 [30]3 years ago

8 0

Y1-y2 over x1- x2 you should be able to figure it out after this formula

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Find four rational number between 1/4 and 2/3.

olya-2409 [2.1K]

Answer:

4/12, 5/12, 6/12, 7/12

Step-by-step explanation:

1/4 x 3/3 = 3/12

2/3 x 4/4 = 8/12

between 3/12 and 8/12

4/12, 5/12, 6/12, 7/12

you can simplify these if you wish

Hope that helped!!! k

6 0

3 years ago

If 2x-3(x+4)=-5 then x=

Mrrafil [7]

2x - 3(x + 4) = -5
2x - 3x - 12 = -5
-x - 12 = -5
-x = -5 + 12
-x = 7
x = -7

The answer is: x = -7.

5 0

2 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

The second of two numbers is 8 less than twice the first. their sum is 19. Find the two numbers

Radda [10]

The first number is 9 and the second number is 10. 10+9=10. 9*2=18 and 10 is 8 less than 18. All the requirements of the numbers are met.

3 0

2 years ago

What is 3-2y+(-8y)+8.4 as a simplified expression

IRISSAK [1]

Answer:

-10y + 11.4

I hope this helps you out

7 0

3 years ago

Read 2 more answers