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3 years ago

Which is bigger .72 or .725?

1 answer:

3 0

.72
.725 would be less because it has more behind the decimal.
.72 would be more because there are only 2 numbers behind the decimal

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What is m∠ MHJ?<br> 35<br> 50<br> 72.5<br> 92.5

NNADVOKAT [17]

Answer:

Step-by-step explanation:

MHJ and LHK are vertical angles, which means they are equal

2x-20 = x+15

Subtract x from each side

2x-20-x = x+15-x

x-20 = 15

Add 20 to each side

x-20+20 = 15+20

x = 35

We want to find MHJ

MHJ =2x-20

=2(35) -20

= 70 -20

= 50

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4 years ago

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The distance across a swimming pool is 6 1/3 yards. If ward swims back and forth across the pool 10 1/2 times, what distance, D,

Sloan [31]

It is about 66.5 yards.

7 0

3 years ago

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What is the property of this equation? if 2x=8 then x=4

Eva8 [605]

Answer is 2 x 4=8 this is a scientific property

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3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

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3 years ago

For her book club, Sharon reads for 45 minutes each day. Write an expression for the number of hours she reads in d days?

VMariaS [17]

H=45d h stands for hours and 45d means 45 minutes per day

3 0

3 years ago

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