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nasty-shy [4]
3 years ago
8

PLS HELP FIRST TO ANSWER GETS BRAINLEST

Mathematics
1 answer:
galben [10]3 years ago
5 0

Answer:

24

multiply them

Step-by-step explanation:

1s-1t-1n

1s-2t-1n

1s-3t-1n

1s-4t-1n

1s-1t-2n

1s-1t-3n

2s-1t-1n

2s-2t-1n

2s-3t-1n

2s-4t-1n

2s-1t-2n

2s-1t-3n

3s-1t-1n

3s-2t-1n

3s-3t-1n

3s-4t-1n

3s-1t-2n

3s-1t-3n

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Solve this identifying holes, vertical asymptotes, and horizontal asymptotes for
USPshnik [31]

x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{Vertical asymptotes:}\\\\(x+4)(x-1)=0\iff x+4=0\ \vee\ x-1=0\\\\\boxed{x=-4\ and\ x=1}\\\\\text{Horizontal asymptotes:}

\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}

6 0
3 years ago
the length of a rectangle is 6 meters less than twice the width. The area of the rectangle is 140m². Find the dimensions of the
AveGali [126]

Answer:

Here's what we know:

A = Lw (Area is length times width)

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(w + m)(w - n)

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140 = 20 * 7

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2 years ago
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d=a+b+c

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Answer:

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