Answer:
<h2>m < 1</h2>
Step-by-step explanation:
![m](https://tex.z-dn.net/?f=m%3C4%2Bm%3C5%2Bm%3C6%5Cqquad%5Ctext%7Bsubtract%20m%20from%20all%20sides%7D%5C%5C%5C%5Cm-m%3C4%2Bm-m%3C5%2Bm-m%3C6-m%5C%5C%5C%5C0%3C4%3C5%3C6-m%5Cto%205%3C6-m%5Cqquad%5Ctext%7Bsubtract%206%20from%20both%20sides%7D%5C%5C%5C%5C-1%3C-m%5Cqquad%5Ctext%7Bchange%20the%20signs%7D%5C%5C%5C%5C1%3Em%5Cto%20m%3C1)
How could it be a fraction? All the numbers are whole & no division? May I assume the #s listed next to each other are multiplied, i.e. 7 2? If so,...
multiply first...
14 * 15 + 10*3 + 1755 (9*13*15)
210 + 30 + 1755
1,995
Answer:
y - intercept. = 2.
Step-by-step explanation:
Given : The equation of a line is 5x − 3y = 6.
To find : Which is the y-intercept of the line.
Solution : We have given 5x − 3y = 6.
Equation of line y = mx +b
Where , m = slope , y intercept = b
Now we convert the 5x − 3y = 6 in line form y = mx +b
5x − 3y = 6
On subtracting both sides by 5x
-3x = - 5x + 6
On dividing both sides by - 3.
x =
.
We cans see m =
, y - intercept. = 2.
Therefore, y - intercept. = 2.
Answer:
Step-by-step explanation:
The relevant relations here are ...
- the sum of arc measures in a semicircle is 180°
- the sum of angles in a triangle is 180°
<h3>Arc measures</h3>
The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:
arc DA = 180° -CD = 180° -125° = 55°
Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.
∠ABO = 90° -∠AOB = 90° -55°
∠ABO = 35°
<h3>Triangle angles</h3>
In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.
∠ACB = 90° -∠ABC = 90° -55°
∠ACB = 35°
In the figure, angles ABO and ACB have measures of 35°.
Answer:
7-4=7+(-4) this is what the equation is looking like when finished