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Olin [163]
4 years ago
6

. An early method of measuring the speed of light makes use of a rotating slotted wheel. A beam of light passes through a slot a

t the outside edge of the wheel, travels to a distant mirror, and returns to the wheel just in time to pass through the next slot in the wheel. One such slotted wheel has a radius of 5 cm and 500 slots at its edge. Measurements taken when the mirror was L = 500 m from the wheel indicated a speed of light of 3.0 x10^5 km/s.. What was the (constant) angular speed of the wheel?. (b) What was the linear speed of a point on the edge of the wheel?
Physics
1 answer:
amid [387]4 years ago
8 0
The time to travel to the mirror and back was 
<span>t=450/3E+8 </span>

<span>The distance from one slot to another is </span>
<span>2*pi*0.05/550 </span>

<span>the time to rotate the distance was </span>
<span>t=2*pi/(w*550) </span>

<span>combine </span>
<span>2*pi/(w*550)=450/3E+8 </span>
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Calculate the speed with which the moon orbits the earth given the distance from earth to moon as R = 3.84 · 108 m. (Astronomers
marshall27 [118]
This sounds pretty easy, in fact. The orbital motion can be assumed to be circular and with constant speed. Then, the period is the time to do one revolution. The distance is the length of a revolution. That is 2*pi*R, where R is the distance between the Moon and the Earth (the respective centers to be precise). In summary, it's like a simple motion with constant speed:

v = 2*pi*R/T,

you have R in m and T is days, which multiplied by 86,400 s/day gives T in seconds.

Then v = 2*pi*3.84*10^8/(27.3*86,400) = 1,022.9 m/s ~ 1 km/s (about 3 times the speed of sound :)

For the Earth around the Sun, it would be v = 2*pi*149.5*10^9/(365*86,400)~ 29.8 km/s!

I know it's not in the problem, but it's interesting to know how fast the Earth moves around the Sun! And yet we do not feel it (that's one of the reasons some ancient people thought crazy the Earth not being at the center, there would be such strong winds!)
3 0
3 years ago
A bicycle pedal is pushed straight downwards by a foot with a 16 Newton force. The shaft of the pedal is 20 cm long. If the shaf
BartSMP [9]

Answer:

2.56 N*m

Explanation:

Torque is force times distance, with the force being perpendicular to the distance.

If the force and distance are not perpendicular, a projection of one of the two must be used instead.

We will use the projection of the length of the shaft upon a perpendicular of the force applied. This will have a magnitude of:

Lh = L * cos(a) (I name it Lh because it is a horizontal projection in this case)

Lh = 0.2 * cos(π/5) = 0.16 m

Then:

T = f * d

T = 16 * 0.16 = 2.56 N*m

6 0
3 years ago
If a chemical reaction has a AH value of -125 kJ, it would be considered what?
Snezhnost [94]

Answer:  

Exothermic Reaction  

Explanation:  

<u>ENDOTHERMIC REACTION</u>: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.

The value of enthalpy change ΔH is positive in such reactions showing intake of energy.

<u>EXOTHERMIC REACTION</u>: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.

The value of enthalpy change ΔH is negative in such reactions showing the release of energy.

Since, the value of ΔH = -125 KJ, is negative for the given reaction.

Therefore, it would be considered as <u>Exothermic Reaction.</u>

7 0
3 years ago
An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
When does a scientist create the conclusion?
Gre4nikov [31]


The best answer is d - while comparing the data with the hypothesis. The scientific method defines the correct steps as:

1. observation - use of the five senses to learn about something.

2. Question - where you raise questions based on your observation.

3. Hypothesis - a prediction or guess of what the answer to the question is.

4. Method - point where you test the hypothesis by carrying out an experiment.

5. Results / data - this is what happened after each step of the experiment.

6. Conclusion - where the results of the experiment are discussed and it  is summarized if the prediction was true or not, based on data from the results.


5 0
4 years ago
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