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Semenov [28]
3 years ago
5

Is block b speeding up or slowing down once it is set into downward motion and the cat is on block a?

Physics
1 answer:
stepan [7]3 years ago
6 0

Answer:

The answer is "Slowing down ".

Explanation:

please find the complete question in the attached file.

In this question, if the block B weight were accounted for by kinetic the friction of frame A, because the blocks pushed at a consistent speed throughout the beginning.

Afterward, on block A, the resistance intensity rises, which allows frames to also be negative, which is defined in the graph, that's why the answer Slowing down is correct.

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If six moles of hydrogen chloride (HCl) react with plenty of aluminum, how many moles of aluminum chloride (AlCl3) will the reac
AlexFokin [52]

Answer:

Two moles of aluminum chloride (AlCl_3) are produced when six miles of hydrogen Chloride (HCl) react with plenty of aluminum

Explanation:

6 Moles of HCl will only react with 2 moles of Al irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of AlCl_3 and 3 moles of H_2 this ratio will also be constant.

So, six moles of hydrogen chloride (HCl) will react with plenty of aluminum to produce many 2 moles of aluminum chloride (AlCl_3).

5 0
3 years ago
When dribbling you should?
Hoochie [10]
D all of the above (:
6 0
3 years ago
Which scenario is an application of Newtons Second Law of Motion?
svlad2 [7]
D would be the answer because The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
4 0
3 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the man

In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

m=\frac{\Delta U}{g\Delta h}=\frac{4620 J}{(9.8 m/s^2)(8.4 m)}=56 kg

6 0
3 years ago
Read 2 more answers
PLEASE HELP AND HURRY
andreyandreev [35.5K]
C
I took the tests earlier hope this helps
7 0
4 years ago
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