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3 years ago

The temperature measurement scale that begins at absolute zero is

Physics

2 answers:

labwork [276]3 years ago

6 0

A. Kevin hhghghhggb bbhbggj

ikadub [295]3 years ago

4 0

<h3>Answer: A. Kelvin</h3>

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Explanation:

At 0 Kelvin, we're at the coldest temperature possible which is referred to as absolute zero. We cannot get any colder than this. At this temperature, the molecules aren't moving or vibrating to provide heat energy. The higher the temperature, the more the molecules are moving or vibrating.

The 0 degree mark on the Celsius scale is well above absolute zero. So that allows for negative Celsius temperatures to be possible. The same can be said about Fahrenheit as well. We cannot have negative Kelvin temperatures.

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1. A ball falls from a height "h" from a tower. Which of the following statements is true?

Strike441 [17]

Answer:

the total kinetic and potential energy of the ball is constant (mechanical energy remains the same)

Explanation:

As the ball falls, kinetic energy is increased in direct relation with the decrease in potential energy

ΔKE + ΔPE = 0

4 0

3 years ago

A uniform log of length L is inclined 30° from the horizontal when supported by a frictionless rock located 0.6L from its left e

mafiozo [28]

Answer:

x = 0.974 L

Explanation:

given,

length of inclination of log = 30°

mass of log = 200 Kg

rock is located at = 0.6 L

L is the length of the log

mass of engineer = 53.5 Kg

let x be the distance from left at which log is horizontal.

For log to be horizontal system should be in equilibrium

∑ M = 0

mass of the log will be concentrated at the center

distance of rock from CM of log = 0.1 L

now,

∑ M = 0

$m_{log} g \times 0.1 L = m_{engineer} g \times (x - 0.6 L)$

$200 \times 0.1 L = 53.5 \times (x - 0.6 L)$

$0.374 L =x - 0.6 L$

x = 0.974 L

hence, distance of the engineer from the left side is equal to x = 0.974 L

7 0

3 years ago

A 4.4 nC charge exerts a repulsive force of 36 mN on a second charge which is located

zhenek [66]

The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.

They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.

The given data in the problem is;

q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C

F is the repulsive force = 36 mN =36 ×10⁶ N

d is the distance = 0.70 m

The Coulomb force is found as;

$\rm F = \frac{Kq_1q_2}{r^2}\\\\\ \rm 36\times 10^6 = \frac{9 \times 10^9 }{(0.7)^2} \times 4.4 \times 10^{-9} \times q_2\\\\\ q_2 = 8.6241 \times 10^{-19 } \ C$