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3 years ago

The temperature measurement scale that begins at absolute zero is

Physics

2 answers:

labwork [276]3 years ago

6 0

A. Kevin hhghghhggb bbhbggj

ikadub [295]3 years ago

4 0

<h3>Answer: A. Kelvin</h3>

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Explanation:

At 0 Kelvin, we're at the coldest temperature possible which is referred to as absolute zero. We cannot get any colder than this. At this temperature, the molecules aren't moving or vibrating to provide heat energy. The higher the temperature, the more the molecules are moving or vibrating.

The 0 degree mark on the Celsius scale is well above absolute zero. So that allows for negative Celsius temperatures to be possible. The same can be said about Fahrenheit as well. We cannot have negative Kelvin temperatures.

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Suppose you lift a 300N object 5m from the floor. How much work did you do on the<br> object?

Mandarinka [93]

Answer:

W= 1500J

Explanation:

<u>Formula:</u> W=f*d

<em>What are your values?</em>

W- ?

F- 300N

D- 5m

<em>Plug in the values.</em>

W= (300N)(5m)

W= 1500J

hope this helps!!

3 0

3 years ago

Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object,which is at 500 K

Damm [24]

Explanation:

The given data is as follows.

$T_{1}$ = 400 K, $T_{2}$ = 500 K,

$\Delta Q$ = 25 kJ = 25000 J (as 1 kJ = 1000 J)

Now, we will calculate the change in entropy as follows.

$\Delta S = \frac{\Delta Q}{\Delta T}$

Putting the given values into the above formula as follows.

$\Delta S = \frac{\Delta Q}{\Delta T}$

= $\frac{25000 J}{(500 K - 400 K)}$

= 250 J/K

Hence, we can conclude that change in entropy is 250 J/K.

4 0

3 years ago

A wire carries a 2a current. what is the current in a second wire that delivers twice as much charge in the same amount of time?

Soloha48 [4]

Answer:

Explanation:

Current is charge per time. So if the second wire delivers twice as much charge in the same amount of time, it must have twice the current.

2 × 2A = 4A

7 0

3 years ago

An atom with five protons six neutrons and five electrons has an atomic mass of

Ainat [17]

The atomic mass of this question is 10.811

4 0

4 years ago

A 50g ball is released from rest 1.0 above the bottom of thetrack

ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

Mass of ball = 50 g

Height = 1.0 m

Angle = 30°

The equation is

$y=\dfrac{1}{4}x^2$

We need to calculate the velocity

Using conservation of energy

$\Delta U_{i}+\Delta K_{i}=\Delta K_{f}+\Delta U_{f}$

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

$\Delta U_{i}=\Delta K_{f}$

Put the value into the formula

$mgh=\dfrac{1}{2}mv^2$

Put the value into the formula

$50\times10^{-3}\times9.8\times1.0=\dfrac{1}{2}\times50\times10^{-3}\times v^2$

$v^2=\dfrac{2\times50\times10^{-3}\times9.8\times1.0}{50\times10^{-3}}$

$v=\sqrt{19.6}$

$v=4.42\ m/s$

We need to calculate the maximum height of the ball

Using again conservation of energy

$\dfrac{1}{2}mv^2=mgh$

Here, h = y highest point

Put the value into the formula

$\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h$

$y=\dfrac{0.5\times(4.42)^2}{9.8}$

$y=0.996\ m$

Put the value of y in the given equation

$y=\dfrac{1}{4}x^2$

$x^2=4\times0.996$

$x=\sqrt{4\times0.996}$

$x=1.99\ m\ \approx 2 m$

Hence, The maximum height of the ball is 2 m.

4 0

3 years ago