All categories

3 years ago

Jesse buys a box of assorted granola bars. It includes these flavors:9 chocolate chip

2 answers:

6 0

What are you asking? if you are asking which one she is most likely to pick it would be choclate chip or peanut butter..

uysha [10]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

the scores on a psychology exam were normally distributed with a mean of 56 and a standard deviation of 9. A failing grade on th

bija089 [108]

hey! i got a failing grade! this world is so small.

3 0

3 years ago

Derek has 2 feet of Tasty Cherry Rope. He plans on splitting it evenly between himself and 5 of his friends. How many inches sho

seropon [69]

Answer:

4 inches

Step-by-step explanation:

There are six people total (derek+5 friends)

2 feet = 24 inches

24 inches divided by the 6 people = 4 inches per person

4 0

3 years ago

Find three consecutive odd integers such that the sum of the smallest number and twice the largest number is equal to fifteen mo

inn [45]

Answer:

The three consecutive odd integers are: -11, -13 and -15.

Step-by-step explanation:

Let the smallest number be represented by x. then the three consecutive odd integers are: x, (x + 2) and (x = 4).

The sum of the smallest number and twice the larges number = x + 2(x + 4)

Fifteen more than four times the middle number = 4(x + 2) + 15

So that;

x + 2(x + 4) = 4(x + 2) + 15

x + 2x + 8 = 4x + 8 + 15

3x + 8 = 4x + 23

3x - 4x = 23 - 8

-1x = 15

⇒ x = -15

(x + 2) = (-15 + 2) = -13

(x + 4) = (-15 + 4) = -11

The three consecutive odd integers are: -11, -13 and -15.

7 0

4 years ago

Need helpp fastt plss will give brainliest to who is correct plss helpp

Citrus2011 [14]

Answer:

333 inches = 27.75 feet = 9.25 yards

6 0

3 years ago

The Greater Pittsburgh Area Chamber of Commerce wants to estimate the mean time workers who are employed in the downtown area sp

Valentin [98]

Answer:

98% Confidence interval: (31.74,38.4)

Step-by-step explanation:

We are given the following data set:

29, 38, 38, 33, 38, 21, 45, 34, 40, 37, 37, 42, 30, 29, 35

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{526}{15} = 35.07$

Sum of squares of differences = 506.93

$S.D = \sqrt{\displaystyle\frac{506.93}{14}} = 6.02$

98% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.02} = \pm 2.145$

$35.07 \pm 2.145(\frac{6.02}{\sqrt{15}} ) = 35.07 \pm 3.33 = (31.74,38.4)$

Thus, there is 98% confidence that the population mean number of minutes spent traveling by workers is between 31.74 mins and 38.40

4 0

3 years ago