Two perpendicular lines have slopes that are negative reciprocals of each other, that is, if one slope is a/b, the other is -b/a
the first line 5x+2y=20, 2y=-5x +20, y=-5/2 x+10, the slope is -5/2, so the perpendicular line's slope is 2/5
the equation in point-slope form is (y-2)=(2/5)(x-5)
in slope-intercept form: y=(2/5)x
in standard form: 2x-5y=0

5 0

3 years ago

Can anyone send working of this please ?

andrezito [222]

The parallel lines create similar triangles. Which means sides are proportional...
$\frac{BR}{CS} = \frac{AR}{AS}$
$\frac{BR}{CS} = \frac{10}{14} = \frac{5}{7}$
So if then the ratio of AR to AS = 5/7
Create a proportion with the other similar triangle that contains the shared side:
$\frac{5}{7} = \frac{e}{18}$
Cross multiply
e = $\frac{90}{7}=12 \frac{6}{7}$

4 0

3 years ago