To find the product of 8 and 6 work out 8 multiplied by 6 which is 48
(HoG)(x) = (2x)2 + 4 simply because HoG(x) is actually H(G(x)). So where ever there was an x in H(x) we substitute our value of G(x). Now the only thing left is to put in the 1. so out answer is (2(1))2 + 4 = 8Only in the 6th grade ; )
Answer:
x = 11, y = 8
Step-by-step explanation:
ΔABC and ΔFDE are congruent by the postulate SSS
Equate the congruent sides in the 2 triangles
BC = ED, that is
x + 3 = 14 ( subtract 3 from both sides )
x = 11
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DF = AB, that is
x - y = 3 ← substitute x = 11
11 - y = 3 ( subtract 11 from both sides )
- y = 3 - 11 = - 8 ( multiply both sides by - 1 )
y = 8
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