Question

You've learned about simple circuits and resistors at this point. So, let's talk about how we can power different circuits. Suppose you had one circuit with a 9V battery connected to two 100 ohm light bulbs in series. and a second circuit with a 9V battery connected to two 100 ohm light bulbs in parallel. How does the brightness of the two bulbs in series compare to two bulbs connected in parallel? Which set is dimmer? Explain why and provide visuals.

Answer 1

Answer:

Explanation:

Total resistance of 2 bulb in series

= 100 +100 = 200 ohm

current in each bulb

= 9/200 = .045 A

In case of parallel combination of bulb

total resistance

= 100 x 100 / (100+100)

50 ohm

current in the main circuit

= 9 / 50 A

current in each bulb

= 9 / (2 x 50)

.09

So in the second case current is more , hence heat generated too will be more . So brightness too will be more.

First set (  in  series ) will be dimmer.