Answer:
The pendulum frequency is (c) the same, or very close to it
Explanation:
The simple pendulum corresponds to a simple harmonic movement, to reach this approximation in the expression of the force the sine of the angle (θ) approaches an angle value, this is only true for small angles, generally less than 15º
Sine (15th) = 0.2588
The angle in radians is 15º π / 180º = 0.26180.2588 / 0.2618
The difference between these two values is less than 1.2%
for smaller angle the difference is reduced more
Therefore, the period for both the 5º and 10º angles is almost the same
Seven days after a waxing gibbous moon, the moon will be waning gibbous, and at some point during that seven days, it will have been Full.
Uh are u okay? G tell ur parents i-
Answer:
tex]2.898\times 10^{-7}\ \text{m}[/tex] ultraviolet region
x-ray region
Explanation:
T = Temperature
b = Constant of proportionality = 
= Wavelength

From Wein's law we have

The wavelength of the radiation will be
and it is in the ultraviolet region.


The wavelength of the radiation will be
and it is in the x-ray region.