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GREYUIT [131]
1 year ago
14

An elevator carrying a person of mass m is moving upward and slowing down. How does the magnitude f of the force exerted on the

person by the elevator floor compare with the magnitude mg of the gravitational force?.
Physics
1 answer:
V125BC [204]1 year ago
6 0

The force f of the elevator on the man keeps reducing as the elevator keeps going up while the gravitational force mg keeps increasing moving upwards.

<h3>What is an elevator?</h3>

An elevator is an electrical device that lifts people up and down a tall building or structure.

for the elevator to go up, f > mg.

for the elevator to come down mg > f.

Analysis

since the force on the man is f = ma

where a is the acceleration of the elevator, then it means when a increases,  f will increase and when it decreases, f would decrease. slowing down means a, is decreasing going up and this reduces the force as the elevator keeps going up.

on the other hand, gravity acts faster on bodies that are slower in motion so since g, increases going up, mg would also increase.

Learn more about forces in an elevator : brainly.com/question/13526583

#SPJ1

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A paper filled capacitor is charged to a potential difference of 2.1 V and then disconnected from the charging circuit. The diel
Goryan [66]

Answer:

Part a)

V' = 7.77 Volts

Part b)

k' = 6.27

Explanation:

As we know that capacitor plate is connected across 2.1 V and after charging it is disconnected from the battery

So here we can say that charge on the plates will remain conserved

So we will have

Q = kC(2.1)

now dielectric is removed between the plates of capacitor

so new potential difference between the plates

V' = \frac{Q}{C'}

V' = \frac{kC(2.1)}{C}

V' = 3.7 \times 2.1

V' = 7.77 Volts

Part b)

Now the capacitor plates are again isolated and unknown dielectric is inserted between the plates

So again charge is same so potential difference is given as

V" = \frac{Q}{k'C}

0.59 V = \frac{kCV}{k'C}

0.59 = \frac{3.7}{k'}

k' = 6.27

5 0
3 years ago
Which of the following statements accurately describes work being done.
ivolga24 [154]

Charge is moved of a capacitor

4 0
3 years ago
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Which statement about atmospheric pressure near Earth’s surface is true
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What are the statements?? I need to know the statements so i can help you.
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Calculate the total displacement of a mouse walking along a ruler, if it begins at the x=5cm, and then does the following: It wa
Lana71 [14]
<span>To begin, the mouse walks from 5 to 12 cm, for a displacement of 7 cm. Next, it walks 8 cm in the opposite direction, for a total displacement of (7 + [-8]) or (-1) cm. This leaves the mouse on 4 cm, and then it walks from there to the 7cm location, for a displacement of 7-4 or +3 cm. Adding 3cm to -1cm gives a final displacement of +2cm.</span>
6 0
3 years ago
A convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -3.0 m . An object is 6.0 m from the mi
Artist 52 [7]

A) -2.0 m

Look at the ray diagram attached in the picture, where:

p identifies the location of the object

q identifies the location of the image

F identifies the focus of the mirror

Each tick represents 1 m

We have

p = 6.0 m is the distance of the object from the mirror

f = -3.0 m is the focal length

From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so

q = -2.0 m

This can also be verified by using the mirror equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-3.0 m}-\frac{1}{6.0 m}=-\frac{3}{6.0 cm}\\q = \frac{-6.0 cm}{3}=-2.0 cm

B) Upright and virtual

As we see from the picture, the image is upright, since it has same orientation as the object.

Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,

- An image is said to be real if it is on the same side of the object

- An image is said to be virtual if it is on the opposite side of the mirror

Therefore, this means that the image is virtual.

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2 years ago
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