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GREYUIT [131]
1 year ago
14

An elevator carrying a person of mass m is moving upward and slowing down. How does the magnitude f of the force exerted on the

person by the elevator floor compare with the magnitude mg of the gravitational force?.
Physics
1 answer:
V125BC [204]1 year ago
6 0

The force f of the elevator on the man keeps reducing as the elevator keeps going up while the gravitational force mg keeps increasing moving upwards.

<h3>What is an elevator?</h3>

An elevator is an electrical device that lifts people up and down a tall building or structure.

for the elevator to go up, f > mg.

for the elevator to come down mg > f.

Analysis

since the force on the man is f = ma

where a is the acceleration of the elevator, then it means when a increases,  f will increase and when it decreases, f would decrease. slowing down means a, is decreasing going up and this reduces the force as the elevator keeps going up.

on the other hand, gravity acts faster on bodies that are slower in motion so since g, increases going up, mg would also increase.

Learn more about forces in an elevator : brainly.com/question/13526583

#SPJ1

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On your first trip to Planet X you happen to take along a 180 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r
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Answer:

g_x = 3.0 m / s^2

Explanation:

Given:

- Change in length of spring [email protected] = 22.6 cm

- Time taken for 11 oscillations t = 19.0 s

Find:

- The value of gravitational free fall g_x at plant X:

Solution:

- We will assume a simple harmonic motion of the mass for which Time is:

                                 T  = 2*pi*sqrt(k / m )    ...... 1

- Sum of forces in vertical direction @equilibrium is zero:

                                 F_net = k*x - m*g_x = 0

                                 (k / m) = (g_x / x)    .... 2

- substitute Eq 2 into Eq 1:

                                  2*pi / T = sqrt ( g_x / x )

                                   g_x = (2*pi / T )^2 * x

- Evaluate g_x:

                                  g_x = (2*pi / (19 / 11) )^2 * 0.226

                                  g_x = 3.0 m / s^2

                                 

                       

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Two groups of students were tested to compare their speed working math problems,Each group was given the same problems.One group
Zanzabum
Your hypothesis can be that the group with calculators would finish faster than the group without calculators.
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Two objects have a force of gravity of 100 N. If the distance between both objects decreases by a factor of 7, while the masses
Shkiper50 [21]

The gravitational force <em>F</em> between two masses <em>M</em> and <em>m</em> a distance <em>r</em> apart is

<em>F</em> = <em>G M m</em> / <em>r</em> ²

Decrease the distance by a factor of 7 by replacing <em>r</em> with <em>r</em> / 7, and decrease both masses by a factor of 8 by replacing <em>M</em> and <em>m</em> with <em>M</em> / 8 and <em>m</em> / 8, respectively. Then the new force <em>F*</em> is

<em>F*</em> = <em>G </em>(<em>M</em> / 8) (<em>m</em> / 8) / (<em>r</em> / 7)²

<em>F*</em> = (1/64 × <em>G M m</em>) / (1/49 × <em>r</em> ²)

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