Answer:
sorry ima need to use your page
Step-by-step explanation:
I supppose the answer is F(X)=X²+4, you can use the vertex to confirm.
<h3>
Answer: D) 130.5 degrees</h3>
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Work Shown:
![c^2 = a^2 + b^2 - 2*a*b*\cos(C)\\\\10^2 = 5^2 + 6^2 - 2*5*6*\cos(x)\\\\100 = 25 + 36 - 60*\cos(x)\\\\100 = 61 - 60*\cos(x)\\\\100 - 61 = - 60*\cos(x)\\\\39 = - 60*\cos(x)\\\\\cos(x) = \frac{39}{-60}\\\\\cos(x) = -0.65\\\\x = \arccos(-0.65)\\\\x \approx 130.5416\\\\x \approx 130.5\\\\](https://tex.z-dn.net/?f=c%5E2%20%3D%20a%5E2%20%2B%20b%5E2%20-%202%2Aa%2Ab%2A%5Ccos%28C%29%5C%5C%5C%5C10%5E2%20%3D%205%5E2%20%2B%206%5E2%20-%202%2A5%2A6%2A%5Ccos%28x%29%5C%5C%5C%5C100%20%3D%2025%20%2B%2036%20-%2060%2A%5Ccos%28x%29%5C%5C%5C%5C100%20%3D%2061%20-%2060%2A%5Ccos%28x%29%5C%5C%5C%5C100%20-%2061%20%3D%20-%2060%2A%5Ccos%28x%29%5C%5C%5C%5C39%20%3D%20-%2060%2A%5Ccos%28x%29%5C%5C%5C%5C%5Ccos%28x%29%20%3D%20%5Cfrac%7B39%7D%7B-60%7D%5C%5C%5C%5C%5Ccos%28x%29%20%3D%20-0.65%5C%5C%5C%5Cx%20%3D%20%5Carccos%28-0.65%29%5C%5C%5C%5Cx%20%5Capprox%20130.5416%5C%5C%5C%5Cx%20%5Capprox%20130.5%5C%5C%5C%5C)
Note: I used the law of cosines. Make sure your calculator is in degree mode.
Answer:
the correct points would be one unit to the right, thusly, (2,4) (4,-1) (-2,1)
Step-by-step explanation:
Answer:
:
pls, don't do that
Step-by-step explanation: