Find the sixth term of this geometric sequence 3584,896,224

Mathematics

1 answer:

Alex3 years ago

7 0

Answer:

3.5

Step-by-step explanation:

these are being decided by 4 everytime, so you can just continue the sequence. 3584,896,224,56,14,3.5

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Determine the slope (9,2) and (3,-8)

Oxana [17]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 2~) 
% (c,d)
&&(~ 3 &,& -8~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-2}{3-9}\implies \cfrac{-10}{-6}\implies \cfrac{5}{3}$

7 0

3 years ago

1. Solve x squared + x - 6 by Factoring

Alex

Answer:

x= -3 and x= 2

E. none of the above

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)= 0

(x-2)(x+3)=0

x= -3 and x= 2

5 0

4 years ago

Read 2 more answers

A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long

stepladder [879]

Answer: 1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀ where

a is the acceleration (in this case it is gravity)
v₀ is the initial velocity
h₀ is the initial height

Given:

a = -9.81 (if it wasn't given in your textbook, you can look it up)
v₀ = 12
h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION: 0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

a=-9.81, b=12, c=3

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\$