What is the price per ounce for 10 ounces and the cost is $1.75
1 answer:
Answer:
The price per ounce is $0.175.
Step-by-step explanation:
Given:
Number of ounces = 10
Price of 10 ounces = $1.75
We know that, from unitary method, price of a unit quantity is given as:
Here, the number of quantities correspond to the number of ounces.
Total price corresponds to the price of the 10 ounces which is $1.75.
Now, unit rate or price per ounce is given as:
Price per ounce =
Price per ounce = $0.175
Therefore, the price per ounce is $0.175.
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Answer:
1). 875 seats
2). 25 rows in each section
3). $8400
4). Saving of $360
5). 2105 tickets remained unsold
6). x = 16
Step-by-step explanation:
This question is incomplete; here is the complete question.
A stadium has 10,500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sections. A seat at the premium section costs $48 per game. A seat at the standard section costs $27 per game.
1. How many seats are there in each section?
2. If there are 35 seats in each row, how many rows are in each section?
3. If all the seats in the premium section are sold out for a game, how much will the stadium get from those ticket sales?
4. There are 50 games in each season. A season pass costs $2,040. A season pass holder can go to all the games and have a seat in the premium section. How much can a fan save by buying the season pass?
5. For the night game on Tuesday, 8,395 tickets were sold. How many tickets were left?
6. Write an equation using “x” and then solve the equation. Each VIP boxes can seat X people. If all the seats and VIP boxes are filled up, there are 10,628 audience in the stadium.
1). Number of seats in the stadium = 10500
Number of sections = 2 premium + 10 standard = 12
Number of seats in each section =
2). If the number of seats in each row = 35
Then number of rows in each section =
3). Number of seats in 2 premium sections = 2×875 = 1750
Cost of 1750 seats at the rate of $48 per game = 1750 × 48 = $84000
4). Cost of one ticket in premium section = $48 per game
If the games planned in one season = 50
Then cost of the tickets = 48×50 = $2400
Cost of the season ticket = $2040
Saving on the purchase of one season ticket = 2400 - 2040 = $360
5). For a night game number of tickets sold = 8395
Total number of seats in the stadium = 10500
Tickets remained unsold = 10500 - 8395 = 2105
6). Number of seats in each VIP box = x
Number of VIP boxes = 8
Number of seats in 8 VIP boxes = 8x
Total number of tickets sold = 10500 + 8x
Total number of audience in the stadium = 10628
Then the equation will be
8x + 10500 = 10628
8x = 10628 - 10500
x =