Answer:
Volume of ammonia 3 L.
Explanation:
Given data:
Temperature = 25°C ( 25+273= 298 k)
Pressure = 99.5 kpa (99.5/101 = 0.98 atm)
Volume of nitrogen = 1.50 L
Volume of ammonia = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Moles of nitrogen:
PV = nRT
n = PV/RT
n = 0.98 atm × 1.50 L / 0.0821 atm. L/mol. K × 298 K
n = 1.47 /24.5 /mol
n = 0.06 mol
Now we will compare the moles of nitrogen with ammonia.
N₂ : NH₃
1 : 2
0.06 : 2×0.06 = 0.12 mol
Volume of ammonia:
PV = nRT
V = nRT/P
V = 0.12 mol× 0.0821 atm. L/mol. K × 298 K/ 0.98 atm
V = 2.9 atm. L /0.98 atm
V = 3 L
In order to determine the state of the manganese ion, we will look at the anion bonded to it.
MnN, N = -3 so Mn(III)
MnO, O = -2 so Mn(II)
MnBr2, Br = -2 so Mn(II)
Mn2S3, S = -2 so Mn(III)
Mn3P2, P = -3 so Mn(II)
MnI3, I = -3 so Mn(II)
2.
For this question we will have to check the number of protons of each element from the periodic table. After this, we will remove or add electrons until the desired charge is attained (charge is difference between number of protons and electrons) since the number of protons does not change.
K+: protons = 19, electrons = 18
Cl-: protons = 17, electrons = 18
Fe+2: protons = 26, electrons = 24
A mole of sodium chloride has mass 58.44 grams. You get that from adding the molar masses of sodium and chlorine, which are listed on the periodic table.
<span>58.44 g/mol * 4.40 mol = 257.1 or ≈ 257 grams with 3 significant figures</span>
The answer is 11.0231131%, i hope this helped if it did please help me.
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