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3 years ago

Describe two advantages and two disadvantages of building your 3D model with modeling clay. (5 points)

Chemistry

1 answer:

marishachu [46]3 years ago

8 0

Answer:

A model or simulation is only as good as the rules used to create it. It is very difficult to create an entirely realistic model or simulation because the rules are based on research and past events. The main disadvantage of simulations is that they aren't the real thing.

Explanation:

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An object on top of a building has a GPE of 23,048j and a mass of 39kg, What is the height of the object

kirill115 [55]

Answer:

Explanation:

The height of the object can be found by using the formula

$h = \frac{p}{mg } \\$

where

p is the potential energy

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

$h = \frac{23048}{39 \times 10} = \frac{23048}{390} \\ = 59.0974...$

We have the final answer as

Hope this helps you

3 0

3 years ago

Then, in the light independent photosynthetic reactions, that energy is used to convert co2 into ________.

Svetradugi [14.3K]

In photosynthesis, light energy is used to convert CO2 into carbohydrates.

7 0

3 years ago

How many standard amino acids are there in the human body?

Whitepunk [10]

Answer:

-Theres 20 amino acids in the human body

-The least number of amino acids in a polypeptide are 10

Explanation:

5 0

3 years ago

How many valence electrons does a single neutral phosphorous atom have

eimsori [14]

It has 5 Valence electrons

5 0

3 years ago

A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the

butalik [34]

Answer:

0.172 M

Explanation:

The reaction for the first titration is:

HCl + NaOH → NaCl + H₂O

First we <u>calculate how many HCl moles reacted</u>, using the <em>given concentration and volume</em>:

19.6 mL * 0.189 M = 3.704 mmol HCl

As one HCl mol reacts with one NaOH mol, <em>there are 3.704 NaOH mmoles in 25.0 mL of solution</em>. With that in mind we <u>determine the NaOH solution concentration</u>:

3.704 mmol / 25.0 mL = 0.148 M

As for the second titration:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

We <u>determine how many NaOH moles reacted</u>:

34.9 mL * 0.148 M = 5.165 mmol NaOH

Then we <u>convert NaOH moles into H₃PO₄ moles</u>, using the <em>stoichiometric coefficients</em>:

5.165 mmol NaOH * $\frac{1mmolH_3PO_4}{3mmolNaOH}$ = 1.722 mmol H₃PO₄

Finally we <u>determine the H₃PO₄ solution concentration</u>:

1.722 mmol / 10.0 mL = 0.172 M

5 0

3 years ago