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Mashutka [201]
3 years ago
10

Describe two advantages and two disadvantages of building your 3D model with modeling clay. (5 points)

Chemistry
1 answer:
marishachu [46]3 years ago
8 0

Answer:

A model or simulation is only as good as the rules used to create it. It is very difficult to create an entirely realistic model or simulation because the rules are based on research and past events. The main disadvantage of simulations is that they aren't the real thing.

Explanation:

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What is the length of the hypotenuse of the right triangle ABC in the figure?
Lostsunrise [7]
Triangle ADC is also a right triangle, with D the right angle, and AC the hypotenuse. 
The triangles are similar (right triangles which share an angle (A), so... 
AD/AC = AC/AB 5/6 = 6/AB AB = 6*6/5 = 36/5 = 7.2
8 0
3 years ago
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Suppose a compound is involved in three different reactions denoted R1, R2, and R3. Tripling the concentration of this reactant
pickupchik [31]

Answer:

The order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

Explanation:

The rate of a chemical reaction is the number of moles of reactants consumed per unit time or the number of moles of products formed per unit. the rate of a chemical reaction is affected by the concentration of reactants

The relationship between the rate of a chemical reaction and the concentration of its reactants is given by the rate law or equation.

Generally, the rate equation is given as;

Rate = k[A]ᵃ[B]ᵇ..., where k = rate constant which is independent of concentration of the reactants, [A] = concentration of reactant A, a = order of reaction A, [B] = concentration of reaction B, b = order of reaction B.

For the given reactions R1, R2 and R3

For R1; rate = 3, Concentration = 3[A]

3 = k[A]3ˣ

3¹ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 1

For R2; rate = 9, Concentration = 3[A]

9 = k[A]3ˣ

3² = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 2

For R1; rate = 1, Concentration = 3[A]

1 = k[A]3ˣ

3⁰ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 0

Therefore, the order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

6 0
3 years ago
A gas sample enclosed in a rigid metal container at room temperature (20.0∘C) has an absolute pressure p1. The container is imme
Vlad [161]

Answer : The new absolute pressure is, 1.068\times P_1

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_2}{P_1}=\frac{T_2}{T_1}

where,

P_1 = initial pressure of gas

P_2 = final pressure of gas

T_1 = initial temperature of gas = 20.0^oC=273+20.0=293.0K

T_2 = final temperature of gas = 40.0^oC=273+40.0=313.0K

Now put all the given values in the above equation, we get:

\frac{P_2}{P_1}=\frac{313.0K}{293.0K}

\frac{P_2}{P_1}=1.068

P_2=1.068\times P_1

Therefore, the new absolute pressure is, 1.068\times P_1

5 0
4 years ago
Consider the reaction: 2BrF3(g) --> Br2(g) + 3F2(g)
riadik2000 [5.3K]

Answer : The entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

Explanation :

The given balanced reaction is,

2BrF_3(g)\rightarrow Br_2(g)+3F_2(g)

The expression used for entropy change of reaction (\Delta S^o) is:

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{Br_2}\times \Delta S_f^0_{(Br_2)}+n_{F_2}\times \Delta S_f^0_{(F_2)}]-[n_{BrF_3}\times \Delta S_f^0_{(BrF_3)}]

where,

\Delta S^o = entropy change of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

\Delta S_f^0_{(Br_2)} = 245.463 J/mol.K

\Delta S_f^0_{(F_2)} = 202.78 J/mol.K

\Delta S_f^0_{(BrF_3)} = 292.53 J/mol.K

Now put all the given values in this expression, we get:

\Delta S^o=[1mole\times (245.463J/K.mole)+3mole\times (202.78J/K.mole)}]-[2mole\times (292.53J/K.mole)]

\Delta S^o=268.74J/K

Now we have to calculate the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition.

From the reaction we conclude that,

As, 2 moles of BrF_3 has entropy change = 268.74 J/K

So, 1.62 moles of BrF_3 has entropy change = \frac{1.62}{2}\times 268.74=217.68J/K

Therefore, the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

3 0
4 years ago
Which force keeps the planets from floating off into space?
lesantik [10]

Answer:

Suns gravity

Explanation:

4 0
3 years ago
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