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vlabodo [156]
4 years ago
13

Find the volume of a balloon of a gas at 842 mm Hg and -23 celcius if it’s volume is 915 milliliters at a pressure of 1170 mm Hg

And a temperature of 24 celcius
Chemistry
1 answer:
Ronch [10]4 years ago
5 0

The volume of a balloon f a gas at 842 mm Hg and -23 celsius if it’s volume is 915 milliliters at a pressure of 1170 mm Hg And a temperature of 24 celsius is 0.22 litres

Explanation:

Data given:

Initial volume of the balloon having gas V1= 915ml OR 0.195 L

initial pressure of the gas P1= 1170 mm Hg OR 1.53 atm

initial temperature of the gas T1 = 24 celsius or 273.15 + 24 = 297.15 K

Final pressure of the gas P2 = 842 mm Hg or 1.10 atm

final temperature of the gas T2 = -23 degrees or 273.15 - 23 = 250.15 K

Final volume at final temperature and pressure V2=?

The formula used is of Gas Law:

\frac{P1V1}{T1} = \frac{P2V2}{T2}

V2 = \frac{P1V1T2}{T1P2}

putting the values in the equation:

V2 =  \frac{1.53 X 0.195 X 250.15}{297.15 X 1.10}

V2 = 0.22 litres is the volume

The volume is 0.22 litres at a pressure of 1170 mmHg and temperature of -23 degrees.

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Answer:

Correct option is

B

5 liters of CH

4

(g)NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

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D) 5×10

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