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2 years ago

HELP I DONT KNOW HOW TO DO THIS !!

Chemistry

1 answer:

BlackZzzverrR [31]2 years ago

5 0

Answer:

you divide 71.5 by 2

Explanation:

it's may look intimidating but the question is actually really simple.

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Find the area of a vegetable garden that is 4.83m long and 3.4m wide. Give your answer to the correct significant figure. (use t

sergejj [24]

Answer:

The area of vegetable garden is 16.422 m².

Explanation:

Given data:

Length = 4.83 m

Width = 3.4 m

Area = ?

Solution:

Formula:

Area = length × width

Area is measured in square unit.

By putting the values in formula:

Area = length × width

Area = 4.83 m × 3.4 m

Area = 16.422 m²

The area of vegetable garden is 16.422 m².

5 0

3 years ago

How does cellular respiration identify as a combustion reaction?

Aleksandr-060686 [28]

reactions to break down glucose using oxygen to produce carbon dioxide, water and energy in the form of ATP. ... To balance the oxygen atoms for the reactant side, you need to count 6 atoms from the glucose.

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2 years ago

Please help me with this homework

ella [17]

Answer:

Density is the correct answer choice.

5 0

3 years ago

Read 2 more answers

Classify each organic compound based on the functional group it contains.

bixtya [17]

Answer:

H2C2O1

Explanation:

8 0

2 years ago

An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr

Lera25 [3.4K]

Answer:

$\sigma_y\ =210.2\ MPa$

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

$\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}$

$\sigma_y\ =Yield\ strength$

d = diameter

K =Constant

$\sigma_o\ =material\ constant$

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

$163=\sigma_o+\dfrac{K}{\sqrt 35}$ ------------1

d= 17 μm ,yield strength = 192 MPa

$192=\sigma_o+\dfrac{K}{\sqrt 17}$ ------------2

From equation 1 and 2

$192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}$

K=394.53

By putting the values of K in equation 1

$163=\sigma_o+\dfrac{394.53}{\sqrt 35}$

$\sigma_o\ =96.31\ MPa$

$\sigma_y=96.31+\dfrac{394.53}{\sqrt d}$

Now when d= 12 μm

$\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}$

$\sigma_y\ =210.2\ MPa$

4 0

2 years ago