The question is partially incorrect, because nitration of <span> methyl benzoate results in generation of methyl 3-nitrobenzoate, and not methyl 2-benzoate.
This a because of the present of ester group, which deactivated benzene ring at ortho and para position. Due to this, the electrophile (NO2+) attackes on meta position.
The detailed mechanism is attached below.</span>
Answer:
0.5 mole
Explanation:
C=12u
O=16u
1 mole carbon dioxide=44 grams
so 22grams = 0.5 mole
No..since research can take different format
Answer:
c. 157 KJ
Explanation:
Q= mC dT dT= 100°C(boiling point) - 25°C=75°C
Q= (500 g * 4.184 J/g °C * 75 °C)
Q= 156900 J= 157 KJ
When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now first write the balanced chemical equation
CuSO₄ (aq) + Na₂S (aq) → CuS(s) + Na₂SO₄ (aq)
Now write the net ionic equation
Cu⁺² (aq) + SO₄⁻² (aq) + 2Na⁺ (aq) + S⁻² (aq) → CuS (s) + 2Na⁺ + SO₄⁻² (aq)
So the net ionic equation is
Cu⁺² (aq) + S⁻² (aq) → CuS (s)
Thus from the above conclusion we can say that When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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