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Crazy boy [7]
3 years ago
15

1.Which statement(s) is/are true about a divergent plate boundary? Check all that apply.

Chemistry
2 answers:
Alja [10]3 years ago
7 0

Answer:

I know the first one is c or e but i not sure what the others are, the second one is- wait are you sure your in 6th grade lol? I dont remember learning this

kherson [118]3 years ago
6 0

Answer:

OMG ITS MEHH

Explanation:

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I need help
liubo4ka [24]

The activation energy in the diagram is 43.8 kcal/ mole, letter C. You have to note that activation energy is the energy needed for the reaction to occur and produce products. Therefore, the spike after H2 and I2 is reacted is the activation energy of the reaction.

3 0
4 years ago
Your aunt is sipping on iced tea and fanning herself during a hot South Carolina summer day. You tell her that there is enough e
tiny-mole [99]

Answer:

This is like having enough energy to supply the world for centuries with just 1% of the sea's force? The amount of energy in it can supply energy therefore the one drop of tea is able to run her air conditioning for the rest of her life.

Explanation:

3 0
3 years ago
If the average speed of a car is 45km/s, how far can it travel in 5 seconds?
pochemuha
The answer would be km in 5 seconds
6 0
3 years ago
How many grams of Br2 are needed to completely convert 15.0 g Al to AlBr3 ?
wariber [46]

Answer:

133 g

Explanation:

Step 1: Write the balanced equation

2 Al(s) + 3 Br₂(l) ⇒ 2 AlBr₃(s)

Step 2: Calculate the moles corresponding to 15.0 g of Al

The molar mass of aluminum is 26.98 g/mol. The moles corresponding to 15.0 g of Al are:

15.0g \times \frac{1mol}{26.98g} = 0.556mol

Step 3: Calculate the moles of Br₂ that react with 0.556 moles of Al

The molar ratio of Al to Br₂ is 2:3. The moles of bromine that react with 0.556 moles of aluminum are:

0.556molAl \times \frac{3molBr_2}{2molAl} = 0.834molBr_2

Step 4: Calculate the mass corresponding to 0.834 moles of Br₂

The molar mass of bromine is 159.81 g/mol. The mass corresponding to 0.834 moles of Br₂ is:

0.834mol \times \frac{159.81g}{mol} = 133 g

8 0
3 years ago
Uranium is used in nuclear reactors and is a rare element on earth. Uranium has three common isotopes. If the abundance of 234U
LenaWriter [7]

Answer:

Average atomic mass of uranium= 237.98 amu.

Explanation:

Given data:

Abundance of U²³⁴ = 0.01%

Abundance of U²³⁵ = 0.17%

Abundance of U²³⁸ = 99.28%

Average atomic mass = ?

Solution:

Average atomic mass of uranium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) +(abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass of uranium= (234×0.01)+(235×0.71)+(238×99.28)/100

Average atomic mass of uranium=  2.34 + 166.85 + 23628.64 / 100

Average atomic mass of uranium= 23797.83 / 100

Average atomic mass of uranium= 237.98 amu.

3 0
3 years ago
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