Plz help me. Plz calculate 4(x−2)−3

Mrs. Dobbs wants to replace the grass in her backyard and needs to find the area, in square feet, so she can purchase sod. The a

Dafna11 [192]

Answer: 158 square feet

Step-by-step explanation:

Area of the rectangle is; 128 feet

Area of the triangle is; 30 feet

Area of the triangle + area of the rectangle is; 158 square feet

8 0

3 years ago

Read 2 more answers

a local community college has 860 students. Of these 860 students, 220 ride bicycles. Write the number of bike riders as a fract

Zinaida [17]

Answer:

11/43

Step-by-step explanation:

A local community college has 860 students

Out of this 860 students, 220students ride bikes

Therefore the fraction of bike riders to the number of students can be calculated as follows

= 220/860

= 11/43

4 0

2 years ago

Department started out with 100 pencils and 200 pens during the lat quarter of this year they lost 4% of the pens and 2% of the

o-na [289]

Answer:

The remaining number of the pencil = 98

The remaining number of the pens = 192

Step-by-step explanation:

Here, according to the question:

The number of pencils at the starting at the quarter = 100

The percentage of the lost pencil over the year = 2%

Now, calculating the lost pencil, we get:

2% of 100 = $\frac{2}{100} \times 100 = 2$

⇒The number of lost pencil over the year = 2

So,Number of remaining Pencil = Total pencil - Number of pencil lost

= 100 - 2 = 98

The number of pens at the starting at the quarter = 200

The percentage of the lost pens over the year = 4%

Now, calculating the lost pens, we get:

4% of 200 = $\frac{4}{100} \times 200 = 8$

⇒The number of lost pens over the year = 8

So,Number of remaining Pens = Total pens - Number of pens lost

= 200 - 8 = 192

Hence, the remaining number of the pencil = 98

And and the remaining number of the pens at the end of the year = 192

6 0

2 years ago

Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute

Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so $\mu = 35$

Variance = 81. The standard deviation is the square root of the variance, so $\sigma = \sqrt{81} = 9$ .

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, $z = -0.44$ has a pvalue of 0.333. So what is the value of X when $z = -0.44$ .

$Z = \frac{X - \mu}{\sigma}$

$-0.44 = \frac{X - 35}{9}$

$X - 35 = -3.96$

$X = 31.04$

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of $X = 40.5$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40.5 - 35}{9}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if $P_{1} = 100% - 72.91% = 27.09% = 0.2709$

$P_{2}$ is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

$X = 38.5$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{38.5 - 35}{9}$

$Z = 0.39$

$Z = 0.39$ has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if $P_{1} = 100% - 65.17% = 34.83% = 0.3483$

So:

$P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192$

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

7 0

3 years ago

If the family spent 151 dollars then how many people went?

Pavel [41]

Answer:

y=21x+25

x=6

Step-by-step explanation:

151=21x+25

-25. -25

126=21x

÷21. ÷21

x=6

3 0

3 years ago