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worty [1.4K]
3 years ago
5

Simplify 22x-13y+19-17y-43x+12

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

-21x-30y+31

Step-by-step explanation:

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Simplify 7n - 1 - 9n + 5
Bumek [7]

Answer: the answer is -2n + 4

8 0
3 years ago
Let |a| = 12 at an angle of 25° and |b| = 7 at an angle of 105°. What is the magnitude of a + b? Round to the nearest decimal.
FromTheMoon [43]

Answer:

It is 15.4 on edge. C

Step-by-step explanation:

6 0
2 years ago
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Write the equation of the line that passes through the points (1,9) and (-1,1). Put
SpyIntel [72]

Answer:

Point slope form

                 y - 9 = 4(x-1)

Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is    4 x - y +5=0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the points are (1,9) and (-1,1)

slope of the line

                m = \frac{y_{2}-y_{1}  }{x_{2} - x_{1} }

               m = \frac{1-9}{-1-1}

             m = 4

<u><em>step(ii):-</em></u>

Equation of the straight line passing through the point (1,9) and slope 'm' = 4

                     y-y₁ = m( x-x₁)

                   y - 9 = 4(x-1)

                  y -9 = 4x-4

           4 x - y -4+9 =0

          4 x - y +5=0

Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is    4 x - y +5=0

7 0
2 years ago
Write the number 68,127,000,000,000,000 in scientific notation.
jolli1 [7]

The answer to this question is 6.8 x 10^16.

8 0
2 years ago
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Evaluate the difference quotient for the given function.
kherson [118]

Assuming you mean f(t) = g(t) × h(t), notice that

f(t) = g(t) × h(t) = cos(t) sin(t) = 1/2 sin(2t)

Then the difference quotient of f is

\dfrac{\frac12 \sin(2(t+h)) - \frac12 \sin(2t)}h = \dfrac{\sin(2t+2h) - \sin(2t)}{2h}

Recall the angle sum identity for sine:

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

Then we can write the difference quotient as

\dfrac{\sin(2t)\cos(2h) + \cos(2t)\sin(2h) - \sin(2t)}{2h}

or

\boxed{\sin(2t)\dfrac{\cos(2h)-1}{2h} + \cos(2t)\dfrac{\sin(2h)}{2h}}

(As a bonus, notice that as h approaches 0, we have (cos(2h) - 1)/(2h) → 0 and sin(2h)/(2h) → 1, so we recover the derivative of f(t) as cos(2t).)

7 0
2 years ago
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