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Alenkasestr [34]
3 years ago
8

Provide a structure for the following compound: C9H10O3; IR: 2400–3200, 1700, 1630 cm–1; 1H NMR: δ 1.53 (3H, t, J = 8 Hz); δ 4.3

2 (2H, q, J = 8 Hz); δ 7.08, δ 8.13 (4H, pair of leaning doublets, J = 10 Hz); δ 10 (1H, broad, disappears with D2O shake)

Chemistry
1 answer:
Svet_ta [14]3 years ago
4 0

Answer:

The answer is Ethyl 3-hydroxybenzoate (structure attached).

Explanation:

The following can be elucidated from IR table of values:

2400- 3200 cm-1 ⇒ Carboxylic acid

17000 cm-1 ⇒ C=O bond (aldehyde, ketone)

1630 cm-1 ⇒ C=C (alkene) or aromatics

H NMR values:

1.53 ⇒ CH3 next to an electronegative, hence the high chemical shift (deshielded)

4.32⇒CH2 next to a CH3 and an R group (possible deshielding)

7.08, 8.13 ⇒ aromatics.

The structure is attached.

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Cathode: Hydrogen gas

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Explanation:

① Write down the ions present in the electrolyte

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Anions: Cl⁻ , OH⁻

② Decide which ions are preferentially discharged.

These are the factors:

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In this case:

For cations, H⁺ ions are selectively discharged at the cathode as its position is lower than Na⁺ in the reactivity series.

Anion: Cl⁻ ions, being more concentrated, are selectively discharged at the anode.

☆For electrolysis,

Cation at the cathode (-ve terminal)

Anion at the anode (+ve terminal)

In summary, here's what happened at each electrode:

<u>C</u><u>athode</u>

- H⁺ selectively discharged

- ionic half equation: 2H⁺ (aq) +2e⁻ → H₂ (g)

<u>Anode</u>

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