Provide a structure for the following compound: C9H10O3; IR: 2400–3200, 1700, 1630 cm–1; 1H NMR: δ 1.53 (3H, t, J = 8 Hz); δ 4.3
2 (2H, q, J = 8 Hz); δ 7.08, δ 8.13 (4H, pair of leaning doublets, J = 10 Hz); δ 10 (1H, broad, disappears with D2O shake)
1 answer:
Answer:
The answer is Ethyl 3-hydroxybenzoate (structure attached).
Explanation:
The following can be elucidated from IR table of values:
2400- 3200 cm-1 ⇒ Carboxylic acid
17000 cm-1 ⇒ C=O bond (aldehyde, ketone)
1630 cm-1 ⇒ C=C (alkene) or aromatics
H NMR values:
1.53 ⇒ CH3 next to an electronegative, hence the high chemical shift (deshielded)
4.32⇒CH2 next to a CH3 and an R group (possible deshielding)
7.08, 8.13 ⇒ aromatics.
The structure is attached.
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Answer:
1)4×10^13Hz
2) 9.95×10-9J
Explanation:
From the image attached, it is clear that the work function of the palladium metal must first be obtained in joules. Then, the frequency is obtained from E=hf.
The kinetic energy if the photoelectrons is obtained as the difference between the energy of the photon and the work function of the metal.
