<span>Vinegar and baking soda react to form a new gaseous substance.
</span><span>The reaction between Vinegar and baking soda has been one of the most common examples of Chemical Reaction.</span>
Answer:
pH of buffer solution is 7.0
Initial pH of Weak acid is 3.27
Final pH of weak acid is 3.07
Amount of NaOH added is 1ml
Explanation:
Titration is a process in which acid and base are introduced together until a neutral solution is achieved whose pH value is near to buffer solution which is 7.0, the pH value for acid is below 7 while pH value for base is above 7.
Volume is an extensive physical property and not an intensive one.
Answer:
The answers are in the explanation
Explanation:
A buffer is the mixture of a weak acid with its conjugate base or vice versa. Thus:
<em>1)</em> Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF. <em>Will </em>result in a buffer because HF is a weak acid and KF is its conjugate base.
<em>2)</em> Mixing 100.0 mL of 0.1 M NH₃ with 100.0 mL of 0.1 M NH₄Br. <em>Will not </em>result in a buffer because NH₃ is a strong base.
<em>3) </em>Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH. <em>Will </em>result in a buffer because HCN is a weak acid and its reaction with KOH will produce CN⁻ that is its conjugate base.
<em>4)</em> Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl <em>Will not </em>result in a buffer because HCl is a strong acid.
<em>5)</em> Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH <em>Will not </em>result in a buffer because each HCN will react with KOH producing CN⁻, that means that you will have just CN⁻ (Conjugate base) without HCN (Weak acid).
I hope it helps!
The solubility equilibrium of PbCl
:
![K_{sp}=[Pb^{2+}][Cl^{-}]^{2}](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%20%20%20)
![[Cl^{-}] = 2.88 * 10^{-2} M](https://tex.z-dn.net/?f=%20%5BCl%5E%7B-%7D%5D%20%3D%202.88%20%2A%2010%5E%7B-2%7D%20M%20)
![[Pb^{2+}]=\frac{[Cl^{-}]}{2} = \frac{2.88 * 10^{-2}}{2}=1.44 *10^{-2}](https://tex.z-dn.net/?f=%20%5BPb%5E%7B2%2B%7D%5D%3D%5Cfrac%7B%5BCl%5E%7B-%7D%5D%7D%7B2%7D%20%3D%20%5Cfrac%7B2.88%20%2A%2010%5E%7B-2%7D%7D%7B2%7D%3D1.44%20%2A10%5E%7B-2%7D%20%20%20%20)
= 
= 
So, the corrected solubility product will be
