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likoan [24]
3 years ago
10

Which produces the greatest number of ions when one mole dissolves in water?

Chemistry
1 answer:
Arada [10]3 years ago
7 0
~Hello there!

Your question: Which produces the greatest number of ions when one mole dissolves in water?

Your answer: Na2SO4<span> can dissociate into three ions, whereas the other choices produce only two ions (or in the case of sucrose, none) when dissolved in water.

Any queries ^?

Happy Studying!
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______is the condition of the atmosphere at any given time and place and ______is the weather over a long period of time (fill i
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Answer:

Temperature is the condition of the atmosphere at any given time and place

and climate is the weather over a long period of time

Explanation:

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7 0
3 years ago
The solubility of oxygen gas in water at 40 ∘c is 1.0 mmol/l of solution. What is this concentration in units of mole fraction?
juin [17]

The formula for mole fraction is:

mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}    -(1)

The solubility of oxygen gas = 1.0 mmol/L  (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

Density = \frac{mass}{volume}

Mass = 1.0 g/ml\times 1000 mL = 1000 g

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = \frac{1000 g}{18 g/mol} = 55.55 mol

Substituting the values in formula (1):

mole fraction = \frac{0.001}{55.55+0.001}

mole fraction = 1.8\times 10^{-5}

Hence, the mole fraction is 1.8\times 10^{-5}.

7 0
3 years ago
How do you draw 5 arrows showing uniformity
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4 0
3 years ago
Gaseous ammonia chemically reacts with oxygen O2 gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of am
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Answer:

1.7 moles of ammonia, NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

Finally, we shall determine the number of mole of ammonia, NH₃, needed to produce 1.7 moles of nitrogen monoxide, NO. This can be obtained as follow:

From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

Therefore, 1.7 moles of NH₃ will also react to produce 1.7 moles of NO.

Thus, 1.7 moles of ammonia, NH₃, is required.

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