A high concentration of water has <u>fewer</u> dissolved particles than a low water concentration.
Most cell membranes are not as easily permeable to many dissolved compounds as water is. There is a quick and constant flow of water. From one area with less dissolved matter to another with more, water transports NET. Or, if you want, from an area with a lot of water to one with little water. The terms isotonic, hypotonic, and hypertonic refer to the concentration of dissolved material. In a medium, such as the extracellular fluid, every distinct material has a concentration gradient that is unique from the gradients of other substances. Every substance will diffuse in line with that gradient as well.
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Complete statement:
Suppose your in the car with the dog. What might be your reference point other than yourself if you determine the the dog is not moving.
Answer:
The car
Explanation:
A reference point is a place or object used for comparison to determine whether something is in motion. If the dog is in the car with me, and the reference point would be the car other than me. For a car, the dog is also not in the motion.
Answer:
- A) pH = 2.42
- B) pH = 12.00
Explanation:
<em>The dissolution of HCl is HCl → H⁺ + Cl⁻</em>
- To solve part A) we need to calculate the concentration of H⁺, to do that we need the moles of H⁺ and the volume.
The problem gives us V=2.5 L, and the moles can be calculated using the molecular weight of HCl, 36.46 g/mol:
= 9.60*10⁻³ mol H⁺
So the concentration of H⁺ is
[H⁺] = 9.60*10⁻³ mol / 2.5 L = 3.84 * 10⁻³ M
pH = -log [H⁺] = -log (3.84 * 10⁻³) = 2.42
- <em>The dissolution of NaOH is NaOH → Na⁺ + OH⁻</em>
- Now we calculate [OH⁻], we already know that V = 2.0 L, and a similar process is used to calculate the moles of OH⁻, keeping in mind the molecular weight of NaOH, 40 g/mol:
= 0.02 mol OH⁻
[OH⁻] = 0.02 mol / 2.0 L = 0.01
pOH = -log [OH⁻] = -log (0.01) = 2.00
With the pOH, we can calculate the pH:
pH + pOH = 14.00
pH + 2.00 = 14.00
pH = 12.00
