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3 years ago

13

An animal cell contains a nucleus and other organelles suspended in a watery solution that is encased in a flexible cell membran

e. Which of the following physical models would best represent an animal cell?

2 answers:

larisa86 [58]3 years ago

4 0

What are the options tell me from comment of this answer

IRISSAK [1]3 years ago

4 0

Answer:

if your from study island the answer is "A plastic zipper bag filled with water, one large plastic bead, and many smaller beads." hope this helps :)

Explanation:

You might be interested in

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Harman [31]

Na₃PO₄ -----> 3Na(+) + PO₄(3-)
y-y.......................3y...........y

3y = 1.2
y = 0,4M

Na₃PO₄ -----> 3Na(+) + PO₄(3-)
0,4-0,4..............1,2..........0,4
0.........................1,2..........0,4

C = n/V
n = C×V
n = 0,4×0,65L
n = 0,26 mol Na₃PO₄

mNa₃PO₄: (23×3)+31+(16×4) = 164 g/mol

164g ----- 1 mol
Xg -------- 0,26 mol
X = 164×0,26
X = 42,64g Na₂SO₄

5 0

3 years ago

valentina_108 [34]

Answer:

Substance 4

Explanation:

Density is defined as mass per unit volume. A substance floats in another when its density is less than that of the substance on which it floats.

If an object is immersed in a denser liquid, it will sink

Since the density of water is 1 g/cm^3, any substance whose density is less than that of water will float in it.

If we look at the table, substance 4 has a density of 0.5g/cm^3. Hence, substance 4 is expected to float in water.

7 0

3 years ago

QUESTION 3<br><br> A large system of stars held in place by mutual gravitation. IT

maxonik [38]

Answer: Galaxy

Explanation: A galaxy is a large system of stars held in place by mutual gravitation.

4 0

3 years ago

A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound

Karolina [17]

Answer:

The empirical formula of the compound is $C_{0.504}HO_{1.008}$ .

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen ( $H$ ) is scaled up to a mole, since it has the molar mass, and both carbon ( $C$ ) and oxygen ( $O$ ) are also scaled up in the same magnitude. The empirical formula is of the form:

$C_{x}HO_{y}$

Where $x$ , $y$ are the number of moles of the carbon and oxygen, respectively.

The scale factor ( $r$ ), no unit, is calculated by the following formula:

$r = \frac{M_{H}}{m_{H}}$ (1)

Where:

$m_{H}$ - Mass of hydrogen, in grams.

$M_{H}$ - Molar mass of hydrogen, in grams per mole.

If we know that $M_{H} = 1.008\,\frac{g}{mol}$ and $m_{H} = 0.2\,g$ , then the scale factor is:

$r = \frac{1.008}{0.2}$

$r = 5.04$

The molar masses of carbon ( $M_{C}$ ) and oxygen ( $M_{O}$ ) are $12.011\,\frac{g}{mol}$ and $15.999\,\frac{g}{mol}$ , then, the respective numbers of moles are: ( $r = 5.04$ , $m_{C} = 1.2\,g$ , $m_{O} = 3.2\,g$ )

Carbon

$n_{C} = \frac{r\cdot m_{C}}{M_{C}}$ (2)

$n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }$

$n_{C} = 0.504\,moles$

Oxygen

$n_{O} = \frac{r\cdot m_{O}}{M_{O}}$ (3)

$n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }$

$n_{O} = 1.008\,moles$

Hence, the empirical formula of the compound is $C_{0.504}HO_{1.008}$ .

3 0

3 years ago

What are the reactants?

tankabanditka [31]

The answer is option 3

6 0

2 years ago