6 hours long, give or take a few minutes, you need to wait to see them arranged in a horizontal line if, at 8 pm, you see that the pointer stars of the big dipper and the star Polaris are arranged in a vertical line.
<h3 /><h3>What do you mean by pointer star?</h3>
The two prominent stars in Ursa Major known as the Pointer Stars can be utilized to locate Polaris, the North Star. The Big Dipper asterism includes the two stars Dubhe and Merak (Alpha and Beta Ursae Majoris). They trace the bowl of the Dipper's exterior. The direction of the North Star is indicated with a line that runs from Merak via Dubhe. Because it identifies the location of the celestial north pole, Polaris is significant in navigation. While other stars and constellations seem to revolve around it, the star is constantly found in the same location in the sky throughout the year.
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This question is incomplete, the complete question is;
The wings of some beetles have closely spaced parallel lines of melanin, causing the wing to act as a reflection grating. Suppose sunlight shines straight onto a beetle wing.
If the melanin lines on the wing are spaced 2.0 μm apart, what is the first-order diffraction angle for green light (λ = 550 nm)?
Answer:
the first-order diffraction angle for green light is 15.96°
Explanation:
Given the data in the question;
from diffraction theory;
nλ = dsin∅
where n is the diffraction order ( 1st order = 1 )
λ is the wavelength ( 550 nm = 550 × 10⁻⁹ m)
d is the grating spacing ( 2.0 μm = 2.0 × 10⁻⁶ m )
∅ is the diffraction angle ( ? )
so we substitute
nλ = dsin∅
sin∅ = nλ / d
sin∅ = (1 × 550 × 10⁻⁹ m) / 2.0 × 10⁻⁶ m
sin∅ = 0.275
∅ = sin⁻¹(0.275)
∅ = 15.96°
Therefore, the first-order diffraction angle for green light is 15.96°
Answer:
The average velocity for the second half of the trip is -2H/T
Explanation:
Given;
time of flight as T
maximum height as H
The maximum height of the flight is given by;
Therefore, the average velocity for the second half of the trip is -2H/T
Answer:
Explanation:
first ball rolls on the porch by total distance
Then again it will move on horizontal floor
also in vertical direction it will drop down
so we have
so magnitude of net displacement of the ball is given as
Answer:
1.118KJ
Explanation:
Potential energy is the energy possessed by a body by virtue of its position.
If the body has a mass (m), and climbs through height (h), the potential energy will be mass×acceleration due to gravity×height
P.E = mgh
Given m = 114kg, g = 9.81m/s² h = 1m
P.E = 114×9.81×1
P.E = 1,118.34Joules
P.E = 1.118KJ
This shows that increase in the gravitational potential energy of the man-earth system is 1.118KJ
