I wish I can help but get Photomath it’ll help you trust :) good luck
Answer:
third option
Step-by-step explanation:
Given
3 ![\left[\begin{array}{ccc}-2&5\\1&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%265%5C%5C1%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiply each element in the matrix by 3
= ![\left[\begin{array}{ccc}3(-2)&3(5)\\3(1)&3(0)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%285%29%5C%5C3%281%29%263%280%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Answer:
Step-by-step explanation:
7w+w-15=17
8w=17+15 add like terms
8w=32 divide
w=32/8=4
now check
7*4+4-15=17
28+4-15=17
17=17
solve:
= 2
Answer:
a. x= 5
Step-by-step explanation:
To solve the question given, we will follow the steps below;
= 2
multiply x to both-side of the equation
× x= 2× x
at the left-hand side of the equation, x will cancel-out x, leaving us with 10
10 = 2x
divide both-side of the equation by 2
10/2 = 2x/2
at the right-hand side of the equation, 2 at the numerator will cancel-out 2 at the denominator leaving us with just x, while on the left-hand side of the equation, 10 will be divided by 2
5 = x
x=5
Answer: 777654
Step-by-step explanation:
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