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Nikitich [7]
3 years ago
10

Which shows three ordered pairs that are all solutions of the equation y = x + 7?

Mathematics
1 answer:
hoa [83]3 years ago
4 0
Plug in both of the numbers for x and y in the equation.
After you do that, you should get B as your answer.
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Math 8 Review:Question 9
forsale [732]

Answer:

$5 per hour

Step-by-step explanation:

Just divide the amount that he earns by the price.

25/5=5

50/10=5

Brett is making $5 an hour.

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3 years ago
Nancy buys 15 m of ribbon. Her sister buys 6 m less ribbon but pays twice as much per metre. Together they pay R66. What is the
Katarina [22]

Answer: 44/9 ----> 22/9

I hope this helps you

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2 years ago
Write an equivalent expression by distributing the "-−" sign outside the parentheses: 10m-(3.3n+1.8)
Jlenok [28]
Sorry I need them points
3 0
2 years ago
Part 2. Laws of sines. Please show work​. Round answer to the nearest tenth.
Bingel [31]

Answer:

5) 30.0m

6) 34.0mi

7) 11.0ft

8) 17.0 km

(all rounded off to the nearest tenth)

Step-by-step explanation:

Please see attached pictures for the full solution.

6 0
2 years ago
Nemecek Brothers make a single product on two separate production lines, A and B. Its labor force is equivalent to 1000 hours pe
frez [133]

Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

8 0
3 years ago
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