Slope=2/3, y-intercept=-5please helphelp

Mathematics

1 answer:

Shtirlitz [24]2 years ago

3 0

What do u need help w
its y=2/3x - 5

You might be interested in

Select all expressions that are equivalent to 12- 4x

snow_lady [41]

I think it’s just A the rest all come out with -12 after being distributed

7 0

3 years ago

What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)

dedylja [7]

Answer:

32 units

Step-by-step explanation:

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = $\sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100}$ = 10 units

BC = $\sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16}$ = 4 units

CD = $\sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36}$ = 6 units

AD = $\sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144}$ = 12 units

Perimeter of ABCD = $10+4+6+12$ = 32 units

6 0

3 years ago

Need quick(Right answer gets brainliest) What is m angle TRS?

Oliga [24]

Answer:

∠TRS = 68°

Step-by-step explanation:

∠TRS + ∠S = 180 - 44 = 136

∠TRS = ∠S

2∠TRS = 136

∠TRS = 68

3 0

2 years ago

HELPPPPPPPPPPPPPPPPPPP

FrozenT [24]

Answer: (A)
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.

Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of $x \geq 3$ . Since the left side has clearly no points common to both graphs. Hence, no solution can exist that will satisfy both.

All of the other graphs have at least one point in common.
(B) has $x \leq -1$
(C) has $x = 1$
(D) has $x \leq -2$