The answer was A but i am found
1.557, -11.557
and hope that helps you
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
Answer:
first one : x=−2y−5z−17
2nd one: x=
3
/2
y−z−8
3rd one: x=
−1
/3
y+
1
/3
z+1
Step-by-step explanation: