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irina1246 [14]
3 years ago
8

What type of light is emitted by electrons falling to the ground state?

Chemistry
1 answer:
Solnce55 [7]3 years ago
3 0
Solar energy is the right awnser

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Please answer ................
nataly862011 [7]

Answer:

Explanation:

i. SO2

ii. Na2O

3 0
2 years ago
Which is the correct lewis structure for barium chloride? which is the correct lewis structure for barium chloride? ..2ba2+[:cl:
wolverine [178]
As Barium belongs to Group II elements (Alkaine Earth Metals), it has two valence electrons in 6 shell, Hence it capable of loosing two electrons and adopting +2 charge as,

                                      Ba    →  Ba⁺²  + 2 e⁻

And Chlorine belongs to Group VII elements (Halogens), it has seven valence electrons in 3rd shell, Hence it is capable of accepting one electron and adopting -1 charge as,

                                       Cl  +  e⁻    →    Cl⁻

Now, for the formation of Barium Chloride we need 2 chloride ions and one Barium cation, as two -1 and one +2 charge can add to form a neutral molecule. Hence,

                                    Ba⁺²  +  2 Cl⁻    →  BaCl₂

8 0
3 years ago
If two gases are present in a container, the total pressure in the container is equal to
qwelly [4]

Answer: sum of the pressure of the two gases present.

Explanation:

According to Dalton's law, the total pressure of a mixture of gases is the sum of individual pressures exerted by the constituent gases.

p_{total}=p_A+p_B

For example if there are there are two gases hydrogen and oxygen with individual pressure of 30 and 20 atm each. Then the total pressure in the container will be:

p_{total}=p_{H_2}+p_{O_2}

Thus p_{total|=30atm+20atm

p_{total}=50atm

Thus if two gases are present in a container, the total pressure in the container is equal to sum of the pressure of the two gases present.

5 0
3 years ago
As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

8 0
3 years ago
A polymer sample combines five different molecular-weight fractions, each of equal weight. The molecular weights of these fracti
kakasveta [241]

Answer:

Mn = 43,783

Mw = 60,000

Mz = 73,333

narrow distribution = 1.37

Explanation:

The molecular weights of these fractions increase from 20,000 to 100,000 in increments of 20,000. This means their Mi is respectively: (The molar weight (Mi) of the fractions)

Fraction 1 : Mi = 20  *10^3

Fraction 2: Mi = 40 *10^3

Fraction 3 : Mi = 60 *10^3

Fraction 4: Mi = 80 *10^3

Fraction 5 : Mi = 100  *10^3

The ΣMi = 300*10^-3

The Wi (mass of the fractions is for all the fractions the same, let's say 1)

So Wi = 1+1+1+1+1 = 5

Since number of moles = mass / Molar mass

The number of moles is respectively: ni = Wi/Mi (x10^5)

Fraction 1 : ni = Wi/Mi = 1/20000 = 5

Fraction 2: ni = 1/40000 = 2.5

Fraction 3 : ni =1/60000 = 1.67

Fraction 4: ni = 1/80000 = 1.25

Fraction 5 : ni= 1/100000 = 1

The Σni = 11.42

Mn = ΣWi/ni = 5/11.42*10^-5 = 43,783

Mw = (ΣWi * Mi)/ΣWi  = 300,000 /5 = 60,000

Mz = (ΣWi * Mi²)/ΣWi *Mi = (4*10^8 +16*10^8 +36*10^8 +64*10^8 +100*10^8) /300,000  =73,333

Mz/Mn = narrow distribution =60,000/43,783 = 1.37

7 0
3 years ago
Read 2 more answers
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