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3 years ago

Which book would a meteorologist most likely use as a reference?

Chemistry

2 answers:

TiliK225 [7]3 years ago

7 0

Answer:

- Predicting the Weather

Hope this helps!

Vitek1552 [10]3 years ago

7 0

Answer:

Predicting the weather

Explanation:

Meteorologist is a scientist that studies the atmosphere with focuses on weather processes and forecasting. A book on "predicting the weather" would most likely be used for reference purposes.

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A sample of neon occupies a volume of 752 ml at 25 0

lyudmila [28]

$V_{initial} = 752\:mL$
$T_{initial} = 25.0^0C$
converting to Kelvin
TK = TC + 273
TK = 25.0 + 273 → TK = 298.0 → $T_{initial} = 298.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 50.0^0C$
TK = TC + 273
TK = 50.0 + 273 → TK = 323.0 → $T_{final} = 323.0\:K$

By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 752 }{ 298.0 } = \frac{ V_{f} }{ 323.0 }$
Product of extremes equals product of means:
$298.0* V_{f} = 752*323.0$
$298.0 V_{f} = 242896$
$V_{f} = \frac{242896}{298.0}$
$\boxed{\boxed{V_{f} \approx 815.08\:mL}}\end{array}}\qquad\quad\checkmark$

5 0

4 years ago

What is the molarity of a 5.00x10^2 mL solution containing 21.1 g of potassium bromide (KBr)? The molar mass of KBr is 119.0 g/m

Dominik [7]

Volume of solution in liters:

5.00 x 10² mL / 1000 => 0.5 L

number of moles:

mass of solute / molar mass

21.1 / 119.0 => 0.1773 moles

Molarity = number of moles / volume

M = 0.1773 / 0.5

M = 0.355 mol/L

Answer C

hope this helps!

5 0

4 years ago

Read 2 more answers

Which of the followings are true about D-glucose and L-glucose? A. They are furanose B. They are stereoisomers C. They are enant

zaharov [31]

Answer:

B. They are stereoisomers

C. They are enantiomers

Explanation:

Let us consider all the options

A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)

B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.

C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions

D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case

E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid

4 0

3 years ago

The principal quantum number (n): specifies the maximum number of electrons. specifies the 3-D shape of the orbital. none of the

kodGreya [7K]

The principal quantum number (n): specifies the principal shell of the orbital.

The answer is option D.

The important quantum number (n) describes the dimensions of the orbital. Orbitals for which n = 2 are larger than those for which n = 1, as an example. Because they have got opposite electric costs, electrons are interested in the nucleus of the atom.

The numerals, called essential quantum numbers, imply strength degrees as well as the relative distance from the nucleus. A 1s electron occupies the energy stage nearest the nucleus.

A 2s electron, less strongly certain, spends most of its time farther far from the nucleus.

Learn more about quantum numbers here: brainly.com/question/11575590

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6 0

2 years ago

if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is

svet-max [94.6K]

Answer:

The volume is increased.

Explanation:

According to Charles' Law, " at constant pressure the volume and temperature of the gas are directly proportional to each other". Mathematically this law is presented as;

V₁ / T₁ = V₂ / T₂ -----(1)

In statement the data given is,

T₁ = 10 °C = 283.15 K ∴ K = 273.15 + °C

T₂ = 20 °C = 293.15 K

So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁ = 100 L

V₂ = Unknown

Now, we will arrange equation 1 for V₂ as,

V₂ = V₁ × T₂ / T₁

Putting values,

V₂ = 100 L × 293.15 K / 283.15 K

V₂ = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

3 0

3 years ago