Please help 20 points and brainly how do u solve 7h= -(2h-18)

Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows

Paul [167]

The value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$

Given to us

The value of cement mixer when bought, $P$ = $ 54,205

the value of cement mixer after 1 year, $P_1$ = $ 47,158. 35

the value of cement mixer after 2 year, $P_2$ = $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

$P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years$

By putting the value, in the formula we get,

$P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13$

Therefore, putting the value of $r$ and $P$ in depreciation formula for $t$ years we get,

$P_n= P(1-r)^n$

$f(t) = 54,205(0. 87)^{t}$

Hence, the value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$ .

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8 0

1 year ago

Xander spends most of his time with his 10 closest friends. he has known 4 of his 10 friends since kindergarten. if he is going

Mademuasel [1]

Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10

Total friends = 10

Friends from kindergarten = 4

Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1

P(E) = Favourable outcomes / Total outcomes

Probability of getting 1st friend from kindergarten = 4/10

Probability of getting 2nd friend from kindergarten = 3/9

Probability of getting 3rd friend not from kindergarten = 6/8

Since all these probabilities are independent, We can use Multiplicative identity. Thus,

Required probability is 4/10 * 3/9 * 6/8

= 1/10

Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10

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5 0

1 year ago

Between the time iko woke up and lunch time the temerature rose by 11°.Then by the time he went to bed ,the temperature dropped

konstantin123 [22]

G(x)=X+11 where y is the total temperature after it rose & x is the temperature when Iko woke up. F(x)= g(x) -14 . Where f(x) is the temperature after it dropped 14 and g(x) is the temperature it was by lunch time.

3 0

2 years ago

An insurance company issues life insurance policies in three separate categories: standard,preferred,and ultra- preferred. Of th

slega [8]

Answer:

a) 0.0002

b) 0.0057

c) 0.0364

Step-by-step explanation:

Lets start by stating the probabilities of a person belonging to each policy:

Standard: 0.3

Preferred: 0.5

Ultra- Preferred: 0.2

The probability of person belonging to each policy AND dying in the next year:

Standard: 0.3 x 0.015 = 0.0045

Preferred: 0.5 x 0.002 = 0.001

Ultra- Preferred: 0.2 x 0.001 = 0.0002

a) The probability a ultra - preferred policy holder dies in the next year is 0.001. To find the probability of a person being both a ultra - preferred policy holder AND die in the next year is: 0.001 x 0.2= 0.0002

b) The probability is given by adding the probabilities calculated before :

0.0045 + 0.001 + 0.0002 = 0.0057

c) We use the results above again. This is 0.0002 / (0.001 + 0.0045). The answer comes out to be 0.0364

6 0

3 years ago

△DEF is shown below. Triangle DEF What is m∠DEF?

S_A_V [24]

Answer:

m∠DEF = 50

Step-by-step explanation:

∠DEG = ∠GEF

3y + 4 = 5y - 10

subtract 4 from both sides

3y = 5y - 14

subtract 5y from both sides

-2y = -14

divide by -2

y = 7

Add 7 into the equations:

3y + 4 + 5y - 10

3(7) + 4 + 5(7) - 10

21 + 4 + 35 - 10

25 + 25

50

4 0

2 years ago